how to ch3 - -Chapter 3, Problem 6 -A displacement vector...

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Sheet1 Page 1 --------------------- Chapter 3, Problem 6 --------------------- Figure > | / | /(35*) |----- Problem 6. Answer (Part A) 27.85 meters Answer (Part B) 19.50 meters How To Solve ~~~~~~~~~~~~~ *See Page 42 *************** A (sub x) = A cos (Degrees) A (sub y) = A sin (Degrees) Part A 1) Plug in A and Degrees A (sub x) = 34 * cos(35) = 27.85116 Answer (A) A (sub x) = 27.85 meters Part B 1) Plug in A and Degrees A (sub y) = 34 * sin(35) = 19.50159884 Answer (B) A (sub y) = 19.50 meters ---------------------- Chapter 3, Problem 10 ---------------------- A displacement vector in the xy plane is 34 m long and directed at angle ? = 35h in Fig. 3-29. Determine (a) the x component a
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Sheet1 Page 2 A person walks in the following pattern: 5.8 km north, then 2.5 km west, and finally 2.6 km south. (a) How far (in km) and (b) a t Answer (Part A) 4.022 kilometers Answer (Part B) How To Solve ~~~~~~~~~~~~~ Pythagorean theorem ******************** a^2 + b^2 = c^2 Inverse Tangent **************** Tan ^(-1) opposit/agacent= x Degrees *Note: There are two possible answers 1) x Degrees 2) 180 - x Degrees Part A 1) Draw the picture and Create a right Triangle 2.5 km |`````| 2.65 km | | . | 5.8 km Point B ^\ | \ | Birds Path \ | \ | . ^ point A 5.8 km - 2.65 km = 3.15 km |\ | \ x 3.15km | \ | \ ````` 2.5km 2) Use the Pythagorean theorem to find the Birds path "x" (3.15)^2 + (2.5)^2 = (x)^2 128.44h (degrees)
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This note was uploaded on 04/12/2008 for the course PHYSICS 150 taught by Professor Naik during the Winter '08 term at University of Michigan.

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how to ch3 - -Chapter 3, Problem 6 -A displacement vector...

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