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Unformatted text preview: new y value which is equal to y*i. It then increases the value of i AFTER it determines the new value of y and increase i until it is equal to 4. The y values in order are as follows y=y*1 y=(3*2)=6 y=(6*3)=18 y=(18*4)=72 This is where the program stops because i is equal to 4 The final display answer is: The result is 72 Problem 5: Error 1: In the for loop there should be a semicolon after i=2 and i>8 Error 2: Instead of x=+1, it should be x+=i Error 3: In the for loop you have to start I out at 1 instead of 2; if you run the program like it is now it would exclude the value of 1 to the sum of the intgers Error 4: I has to be i<8, not i>8 because you are looking for the sum of the numbers before I reaches 8 The output of the program then becomes The sum of integers 1 to 7 is 28; Old Program = New program =...
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This note was uploaded on 02/01/2009 for the course ENGR 001 taught by Professor Dr.smith during the Spring '08 term at Lehigh University .
- Spring '08