Set No 6 Solutions - Problem 1 Emmett studies the...

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Problem 1 Emmett studies the adsorption of argon on 0.606 grams of silica gel at 90 K. Using the BET equations and the data given in the problem statement, calculate the surface area of the adsorbent. The BET equation is given as: () ( ) max max 1 1 vap vap CP P CV CV P VP P =+ where if we plot the above function in the form y=mx+b, we should get a straight line. The vapor pressure of argon at 90 K from Perry’s HB = 1003.96 mm Hg PV P/V(P vap -P) P/P vap mmHg cm 3 (cm 3 ) -1 - 78.46 55.03 1.54E-03 0.078 176.92 72.73 2.94E-03 0.176 224.62 80.00 3.60E-03 0.224 378.46 106.67 5.67E-03 0.377 432.31 117.58 6.43E-03 0.431 515.38 138.18 7.63E-03 0.513 584.62 166.06 8.40E-03 0.582 y = 0.01370x + 0.00051 0E+00 1E-03 2E-03 3E-03 4E-03 5E-03 6E-03 7E-03 8E-03 9E-03 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 P/P vap P/V(P vap -P)
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From the plot we can get the intercept and slop as: max 1 0.01370 CV = ( ) max 1 0.00051 C CV = solve for C and V max max 1 0.01370 V C = thus, ( ) 1 0.00051 1 0.01370 C C C = ⎛⎞ ⎜⎟ ⎝⎠ 1.03723 C = 3 max 70.3214 Vc m = But since on 0.606 grams of sample was used: 33 max 70.3214 116.042 0.606 cm cm V gm gm == thus the surface area: 2 6 max 43500 5.047 10 g cm SV gm
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Problem 2
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Set No 6 Solutions - Problem 1 Emmett studies the...

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