Potassium Alum preperation lab

Potassium Alum preperation lab - PREPARATION OF(POTASSIUM...

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PREPARATION OF (POTASSIUM) ALUM Name ________ ____________ Section______ Week One Form of aluminum used: foil____ Mass of aluminum used: ___0.6672________ Moles of 4M KOH used: ___.1____________________ The balanced equation for the reaction of potassium hydroxide and aluminum: 2 Al(s) + 6 H 2 O(l) + 2 KOH(aq) + heat --> 2 KAl(OH) 4 (aq) + 3 H 2 (g) Moles of 6M H 2 SO 4 used: __.09___________________ The balanced equation(s) for the reaction of sulfuric acid: 2KAl(OH) 4(aq) + 2 H 2 SO 4(aq) --> 2 Al(OH) 3(s) + K 2 SO 4(aq) + 2 H 2 O (l) The balanced equation(s) for the formation of alum from its components: 2Al+2KOH+4H2SO4+22H2O -> 2[KAL(SO4)2 *12H20] + 3H2 Mass of alum crystals obtained: _______3.0075_____________________ Theoretical yield of alum: ____11.7g_______ % yield of alum: _25.7%______ [Show calculations] .6672/26.98= .02473 moles of AL KAl(SO4)2*12H20= 473.168 g per mole 473.168 x .02473 moles= 11.701 grams (11.7-3.0075)/11.7 x 100 -100= 25.7% Week Two :
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Potassium Alum preperation lab - PREPARATION OF(POTASSIUM...

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