This preview shows page 1. Sign up to view the full content.
Unformatted text preview: =760 torr =760 mm Hg PV=nRT PV= N x m= joule R= 8.314472 J/moleK R= .08205745 Latm/moleK k= Bolzmann constant = R/NA= 1.380658 x 10^-23 J/K KE =(1/2)mV^2 =(3/2)kT for one particle KE(mole)=(1/2)(M.W.)V^(-2) =(3/2)RT Boltzmann Distribution (Number of particles at given energy) =(total number of particles)e^(-E/kT) diffusion-how fast a gas is moving through another gas effusion-how fast a molecules of a gas will move through a tiny hole...
View Full Document
This note was uploaded on 04/16/2008 for the course CHEM Chem 1100 taught by Professor Korenowski during the Spring '06 term at Rensselaer Polytechnic Institute.
- Spring '06