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Unformatted text preview: ₃ ₂ H O = 18 g/mol ₂ Actual: 291 g/mol – 183 g/mol = (108 g/mol)/(18 g/mol) = 6 Experimental: Trial 1 = 291 g/mol – 217 g/mol = (74 g/mol)/(18 g/mol) = 4 Trial 2 = 291 g/mol – 219 g/mol = (72g/mol)/(18 g/mol) = 4 Trial 3 = 291 g/mol – 227 g/mol = (64 g/mol)/(18 g/mol) = 4 IV. Conclusions: The concentrations of the unknown solutions were found to be 15.4 g/L, 21.0 g/L, and 25.0 g/L. The formula found after calculations was closest to a trihydrate, but it should have been a hexahydrate like the first solution. There may have been flaws due to some confusion of finding the concentration of the unknown solutions. The bottles containing the solutions stated a value that may have been the concentration, but the values of absorbance recorded would not have matched. The absorbance readings appeared to be correct because the values increased as the concentration increased....
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This note was uploaded on 04/17/2008 for the course CHEM 1151 taught by Professor Splan during the Fall '07 term at University of Minnesota Duluth.
- Fall '07