problem40_11 - h 2 d 2 = E 8 2 m dx 2 d2 d2 d = 2 A cos kx...

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Unformatted text preview: h 2 d 2 . = E. 8 2 m dx 2 d2 d2 d = 2 ( A cos kx) = (- Ak sin kx) = - Ak 2 cos kx 2 dx dx dx Ak 2 h 2 cos kx = EA cos kx 8 2 m 40.11: a) Eq.(40.3) : - k 2h2 8 2 mE 2mE k= = . 2 2 8 m h ) b)This is not an acceptable wave function for a box with rigid walls since we need (0) = ( L) = 0, but this (x) has maxima there. It doesn't satisfy the boundary condition. E= ...
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This note was uploaded on 04/17/2008 for the course PHYS 2306 taught by Professor Ykim during the Spring '06 term at Virginia Tech.

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