DETERMINATION OF THE EQUILIBRIUM CONSTANT LAB REPORT 20120604 - LAB REPORT DETERMINATION OF THE EQUILIBRIUM CONSTANT Submitted By u Submitted To

DETERMINATION OF THE EQUILIBRIUM CONSTANT LAB REPORT 20120604

This preview shows page 1 - 4 out of 8 pages.

LAB REPORT DETERMINATION OF THE EQUILIBRIUM CONSTANT Submitted By: u Submitted To: Submitted Date: June 11, 2012 Purpose Determine the equilibrium constants for reaction
Image of page 1
(CH 3 COOCH 2 CH 3(l) + HOH (l) CH 3 COOH (aq) + CH 3 CH 2 OH (aq) ) by establishing three distinct equilibriums and get their average. Abstract Test Tube 1A and 1B only for determining the amount of HCl aqueous which is also used in tube #2, 3, 4 as a catalyst. Then concentrating on test tube #2, 3, 4 to determine the equilibrium constants for those reactions in different equilibriums: CH 3 COOCH 2 CH 3(l) + HOH (l) CH 3 COOH (aq) + CH 3 CH 2 OH (aq) The equilibrium constant equation is : K eq =[ CH 3 COOH (aq) ][ CH 3 CH 2 OH (aq) ] [CH 3 COOCH 2 CH 3(l) ][ HOH (l) ] Since the reactants and products are all in the same system with the same volume, which is [ CH 3 COOH (aq) ]=n(CH 3 COOH (aq) )/V ; [ CH 3 CH 2 OH (aq) ]=n(CH 3 CH 2 OH (aq) )/V ; [CH 3 COOCH 2 CH 3(l) ]=n(CH 3 COOCH 2 CH 3(l) )/V ; [ HOH (l) ]=n(HOH (l) )/V Therefore the equation can be simplified to be: K eq = [n(CH 3 COOH (aq) )/V][ n(CH 3 CH 2 OH (aq) )/V] [n(CH 3 COOCH 2 CH 3(l) )/V][ n(HOH (l) )/V] = n(CH 3 COOH (aq) )n(CH 3 CH 2 OH (aq) ) n(CH 3 COOCH 2 CH 3(l) )n(HOH (l) ) So the problem is changed into finding the number of moles of reactants and products. Since all of the reactants are not ran out of at the end, so the calculation must be separated: 1) Finding the amount of HCl molecules in the original solution. The # of moles of the HCl is the same as the number of moles of H 3 O + (aq) , since the H 3 O + (aq) are nearly all generated by the ionization of HCl. Titrate by using NaOH (aq) to measure the # of moles of H 3 O + (aq) in the solution. Then according to: mass(HCl)=molar mass·n to calculate the mass of HCl in the HCl aqueous originally. 2) Calculating the amount of HOH in the HCl solution originally. Subtracting the mass of test tube and solution by the mass of only test tube to determine the total mass of chemical – HCl and HOH together. Then by using the total mass of the solution minus the mass of HCl molecules which is already known to determine the mass of H 2 O molecules. Then the number of molecules of HOH is being determined by: n=mass/molar mass.
Image of page 2
3) Average For both 1A and 1B, they have the same function in this lab of determining the amount of HCl and HOH molecules.
Image of page 3

Want to read all 8 pages?

Image of page 4

Want to read all 8 pages?

You've reached the end of your free preview.

Want to read all 8 pages?

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes
A+ icon
Ask Expert Tutors