DETERMINATION OF THE EQUILIBRIUM CONSTANT LAB REPORT 20120604 - LAB REPORT DETERMINATION OF THE EQUILIBRIUM CONSTANT Submitted By u Submitted To

# DETERMINATION OF THE EQUILIBRIUM CONSTANT LAB REPORT 20120604

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LAB REPORT DETERMINATION OF THE EQUILIBRIUM CONSTANT Submitted By: u Submitted To: Submitted Date: June 11, 2012 Purpose Determine the equilibrium constants for reaction
(CH 3 COOCH 2 CH 3(l) + HOH (l) CH 3 COOH (aq) + CH 3 CH 2 OH (aq) ) by establishing three distinct equilibriums and get their average. Abstract Test Tube 1A and 1B only for determining the amount of HCl aqueous which is also used in tube #2, 3, 4 as a catalyst. Then concentrating on test tube #2, 3, 4 to determine the equilibrium constants for those reactions in different equilibriums: CH 3 COOCH 2 CH 3(l) + HOH (l) CH 3 COOH (aq) + CH 3 CH 2 OH (aq) The equilibrium constant equation is : K eq =[ CH 3 COOH (aq) ][ CH 3 CH 2 OH (aq) ] [CH 3 COOCH 2 CH 3(l) ][ HOH (l) ] Since the reactants and products are all in the same system with the same volume, which is [ CH 3 COOH (aq) ]=n(CH 3 COOH (aq) )/V ; [ CH 3 CH 2 OH (aq) ]=n(CH 3 CH 2 OH (aq) )/V ; [CH 3 COOCH 2 CH 3(l) ]=n(CH 3 COOCH 2 CH 3(l) )/V ; [ HOH (l) ]=n(HOH (l) )/V Therefore the equation can be simplified to be: K eq = [n(CH 3 COOH (aq) )/V][ n(CH 3 CH 2 OH (aq) )/V] [n(CH 3 COOCH 2 CH 3(l) )/V][ n(HOH (l) )/V] = n(CH 3 COOH (aq) )n(CH 3 CH 2 OH (aq) ) n(CH 3 COOCH 2 CH 3(l) )n(HOH (l) ) So the problem is changed into finding the number of moles of reactants and products. Since all of the reactants are not ran out of at the end, so the calculation must be separated: 1) Finding the amount of HCl molecules in the original solution. The # of moles of the HCl is the same as the number of moles of H 3 O + (aq) , since the H 3 O + (aq) are nearly all generated by the ionization of HCl. Titrate by using NaOH (aq) to measure the # of moles of H 3 O + (aq) in the solution. Then according to: mass(HCl)=molar mass·n to calculate the mass of HCl in the HCl aqueous originally. 2) Calculating the amount of HOH in the HCl solution originally. Subtracting the mass of test tube and solution by the mass of only test tube to determine the total mass of chemical – HCl and HOH together. Then by using the total mass of the solution minus the mass of HCl molecules which is already known to determine the mass of H 2 O molecules. Then the number of molecules of HOH is being determined by: n=mass/molar mass.
3) Average For both 1A and 1B, they have the same function in this lab of determining the amount of HCl and HOH molecules.

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