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Unformatted text preview: positive peak, which implies that V o2 is minimum and the minimum drainto source voltage to keep the NMOS in saturation is at its maximum. We need to satisfy V o2,min > (V gs – V t ) max , which means V DD1.08V > 1.02V – 0.5V VDD > 1.6V V o1 V o2 V DD 1V 1.02V 0.98V V DD1V V DD1.08V + V dsatV DD0.92V 20mVpeak swing 80mVpeak swing Note: Alternative/approximate solutions that make use of appropriate “small signal” assumptions will also yield full credit....
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 Fall '04
 Murmann,B
 Integrated Circuit, Volt, Englishlanguage films, VO2, The Signal

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