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hw4_sol

# hw4_sol - Solutions to HOMEWORK#4 1a Rout = 1 g m2 Avo = g...

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Solutions to HOMEWORK #4 1a. 3 10 1 1 2 2 1 2 1 1 2 = = = = = = vo D m D m m D D m m m out m vo m out A I g I g g I I g g g R g A g R b. 5 2 1 4 3 2 2 3 10 67 . 5 10 3 10 89 . 1 2 2 × = = × = = = m D dB L m L m dB g I V f C g C g f π π I D = 5.67×10 -5 A I TAIL = 2 I D = 1.134×10 -4 A Using I D /W vs 2/(g m /I D ) plots, find 8 . 18 2 = W I D for g m2 /I D = 10/3 W 2 = I D /18.8 = 3um 18 . 2 1 = W I D for g m1 /I D = 10 W 1 = I D /2.18 = 26um g m1 = g m1 /I D × I D = 5.67×10 -4 1/V g m2 = g m2 /I D × I D = 1.89.×10 -4 1/V c. SPICE DECK * Hw 4, Number 1 *.param k = '2' .param k = '1' + curr = 'k*113.4u' + w1 ='k*26u' + w2 ='k*3u'

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+ len =.5u vic vic 0 1.5 vid vid 0 ac 1 e1 vip vic vid 0 0.5 e2 vic vim vid 0 0.5 itail vdd vs curr vdd vdd 0 0 m1a vom vip vs vs pch214 W='w1' L='len' m1b vop vim vs vs pch214 W='w1' L='len' m2a 0 0 vom vom pch214 W='w2' L='len' m2b 0 0 vop vop pch214 W='w2' L='len' cl1 vop 0 100f cl2 vom 0 100f .op .ac dec 100 1k 10g .tf v(vop) vid .options post brief .lib '/usr/class/ee214/lib/ee214_hspice.txt' nominal .end .op *Note that SPICE says transistors are in cutoff. Obviously, that
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