# hw3 - =&amp;gt BW= 502.48 MHz From ac simulation BW=...

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Problem 1) a)

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Problem 1) b)
Problem 1) c)

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Problem 1) d) Problem 2) a) gm*Rl =2 => gm=2 mA/v b) Id max = 300uw/2 = 150 uA => gm/Id = 13.13 /v c) For NMOS design & L = .35 um : Id/w = 5.25 => w = 29.5 um For NMOS design & L = .5 um : Id/w = 3.5 => w = 43 um d) For NMOS design & L = .35 um : f T = 6.4 GHz For NMOS design & L = .5 um : f T = 3.1 GHz
element 0:mn1 model 0:nch214 region Saturati id 148.5080u ibs 0. ibd 0. vgs 681.0000m vds 1.8515 vbs 0. vth 566.5841m vdsat 110.1638m beta 20.3037m gam eff 894.1238m gm 2.0456m gds 33.0167u gmb 455.0407u cdtot 37.6488f cgtot 51.0292f cstot 98.6479f cbtot 102.1267f cgs 34.7015f cgd 6.6871f Using Miller approximation: BW=1/(2* π *Ri*[Cgs+Cgd*(1+gm*Rl)]) Cgs + Cgd + Cgb = gm/(2* π *f T ) = 49.78 fF Cgd = Col = .23*W fF = 6.785 fF

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Unformatted text preview: =&amp;gt; BW= 502.48 MHz From ac simulation BW= 478 MHz (next graph) Therefore the miller approximation has (502.48-478)/478 = 5.1% error. NMOS bias for L= .5 um &amp;amp; W=43um &amp;amp; Vgs = .716 v: element 0:mn1 model 0:nch214 region Saturati id 150.1687u ibs 0. ibd 0. vgs 716.0000m vds 1.8498 vbs 0. vth 594.4904m vdsat 115.7645m beta 19.4734m gam eff 894.1238m gm 2.0174m gds 8.4515u gmb 614.5373u cdtot 54.6719f cgtot 102.5349f cstot 177.1380f cbtot 160.0336f cgs 77.5140f cgd 10.3387f Using Miller approximation: BW=1/(2* *Ri*[Cgs+Cgd*(1+gm*Rl)]) Cgs + Cgd + Cgb = gm/(2* *f T ) = 102.73 fF Cgd = Col = .23*W fF = 9.89 fF =&amp;gt; BW= 260 MHz From ac simulation BW= 258 MHz (next graph) Therefore the miller approximation has (260-258)/258 = .8% error....
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## This note was uploaded on 04/17/2008 for the course EE 214 taught by Professor Murmann,b during the Fall '04 term at Stanford.

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hw3 - =&amp;gt BW= 502.48 MHz From ac simulation BW=...

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