Exam 2 Sample Exam Answers

Exam 2 Sample Exam Answers - Department of Chemistry CHM...

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Department of Chemistry CHM 1220/1225 Exam II – Sample Exam Solutions (#1 corrected) 1. Na + < F < Cl < S 2– 2. CS e Se 3. Xe F F F F F + 2. Valence electrons: 1(4) + 2(6) =16; bonding: 8; nonbonding: 8 3. Valence electrons: 1(8) + 5(7) -1 =42; bonding: 10; nonbonding: 32 4. C H O O C H O O - - 4. Valence electrons: 1(1) + 1(4) + 2(6) + 1 =18; bonding: 8; nonbonding: 10 5. trigonal planar, trigonal planar; trigonal bipyramidal, see-saw; tetrahedral, trigonal pyramidal 6. Δ H = [2(432 kJ) + 2(745 kJ)] – [2(358 kJ) + 2(411 kJ) + 2(459 kJ)] = -102 kJ 7. sp 2 , three C-O σ -bonds, one C-O π -bond; sp 3 d, four Cl-F σ -bonds; sp 3 , three N-H σ -bonds. 8. a. NO: 7 + 8 = 15 electrons – 4 in KK shell = 11. ( σ 2s ) 2 ( σ * 2s ) 2 ( π 2p ) 4 ( σ 2p ) 2 ( π * 2p ) 1 b. NO bond order = ½ (8 – 3) = 2.5; c. NO + bond order = ½ (8 – 2) = 3;d. NO + has a shorter bond. 9. T 1 = 28.0 + 273.15 = 301.2 K P 1 = 400.0 mmHg T 2 = 46.5 + 273.15 = 319.7 K P 2 = 760.0 mmHg (at the normal boiling point) Δ = K . K . K mol J . H mmHg . mmHg . ln vap 7 319 1 2 301 1 3145 8 0 400 0 760 = Δ
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This test prep was uploaded on 04/17/2008 for the course CHEM 1220 taught by Professor Barber during the Fall '08 term at Wayne State University.

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Exam 2 Sample Exam Answers - Department of Chemistry CHM...

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