Turbine - For 3300 ft/sec the optimal distribution of the...

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Jack Lee October 19, 2007 We at the Great Northern Paper Company have 3 large power generators two that can accept a flow of 1110 ft/sec and a third that can accept 1225 ft/sec flow. Each generator has been found to have an equation that determines its power output in reference to how much flow it receives, with these equations I have found the maximum power output for three different flow rates: 2500, 3300, and 900 ft/sec. For 2500 ft/sec the optimal distribution of the flow is: Generator 1: 777.35 ft/sec Generator2: 762.59 ft/sec Generator3: 960.04 ft/sec This distribution will yield a power output of 28411.67 KW
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Unformatted text preview: For 3300 ft/sec the optimal distribution of the flow is: Generator 1: 1063.48 ft/sec Generator 2: 1011.51 ft/sec Generator3: 1225 ft/sec This distribution of flow will yield a power output of 33573.68 KW For 900 ft/sec the optimal distribution of the flow is: Generator 1: 0 ft/sec Generator 2: 0 ft/sec Generator 3: 900 ft/sec This distribution will yield a power output of 11147.28 KW For the calculations for each of the flow rates, refer to the following pages. The Calculations for each rate are in the same order as presented in this write up. Jack Lee October 19, 2007...
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Turbine - For 3300 ft/sec the optimal distribution of the...

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