Unformatted text preview: T’s of 121 N and 129 N. ____ _____ 5. Since f = (1/2π)√K/m, entering the numbers gives f = (1/2π)√200/5 = 1.01 Hz. 6. There are two approaches here. ____ a) │v max │ = Aω where A = 20 cm or 0.2 m and ω = √K/m . The numbers give v max = 1.26 m/s. b) 1/2mv 2 = 1/2KA 2 where the velocity at x = 0 is the maximum velocity. Here ______ ____ v = √KA 2 /m = A√K/m = 1.26 m/s. 7. Here, no matter the direction of the displacement, one spring pulls and the other pushes so their individual forces are in the same direction, back to the equilibrium position. So the forces add producing a net force whose magnitude is 2Kx, like a spring with double the K. _____ _____ Therefore f = (1/2π)√2K/m = (1/2π)√400/5 = 1.4 Hz....
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- Spring '07
- Force, Displacement, closed pipe, pipe successive harmonics