Exam 2 Solution Key

Exam 2 Solution Key - Chem 10172, Spring 2008 (1) EXAM 2...

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Chem 10172, Spring 2008 EXAM 2 KEY February 28, 2008 1 (1) Consider the molecules acetophenone and styrene, shown below. O Acetophenone Styrene (a) (4 pts.) How would you distinguish acetophenone from styrene using infrared (IR) spectroscopy? Acetophenone will have a strong band at ~1700 cm -1 due to C=O stretching, styrene will not. (b) (4 pts.) Is the 13 C NMR spectrum shown below due to acetophenone or to styrene? Compound (circle one): Acetophenone Styrene
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Chem 10172, Spring 2008 EXAM 2 KEY February 28, 2008 2 (1) continued O Acetophenone Styrene (c) (4 pts.) Is the 1 H NMR spectrum shown below due to acetophenone or to styrene? Compound (circle one): Acetophenone Styrene (d) (4 pts.) To which compound (acetophenone or styrene) does the mass spectrum below correspond? Compound (circle one): Acetophenone Styrene
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Chem 10172, Spring 2008 EXAM 2 KEY February 28, 2008 3 (2) (a) (10 pts.) Indicate which 1 H and 13 C peaks in the spectrum below correspond to the indicated positions in isoamyl acetate (the major component of artificial banana flavor). 1 H _____ 1 H _____ 1 H _____ 13 C_____ 13 C_____ CH 3 H C CH 3 C H 2 H 2 C O C O CH 3 B a b C E (b) (6 pts.) The peak labeled D is shown in expanded view below. State its multiplicity (coupling pattern). On the molecular structure above, circle any protons in isoamyl acetate that are coupled to the proton that gives rise to peak D . Quartet; see figure above for H’s coupled to it. (c)
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This homework help was uploaded on 04/17/2008 for the course BIOS 10161 taught by Professor Tenniswood during the Fall '07 term at Notre Dame.

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Exam 2 Solution Key - Chem 10172, Spring 2008 (1) EXAM 2...

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