hrly_exam_ii_vb_solution.20070919.46f1787c86eb63.04940611

# hrly_exam_ii_vb_solution.20070919.46f1787c86eb63.04940611 -...

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Unformatted text preview: TAM212 Hour Exam II - Spring 2005 Solution- Version B A1) v C = 5 i ω C k × r I C = 5 i ω C k × 1 j = 5 i- ω C i = 5 i ω C =- 5 rad/s v A = ω C k × r I A =- 5 k × 2 j = 10 i m/s v B = v A + ω B k × r AB v B i = 10 i + ω B k × ( r AB,x i + r AB,y j ) v B i = 10 i + ω B k × ( r AB,x i + r AB,y j ) v B i = 10 i + ω B r AB,x j- ω B r AB,y i j components: = ω B r AB,x ω B = i components: v B = 10- ω B r AB,y v B = 10 v B = 10 i m/s A2) From previous problem, we saw that ω B = 0 . a C = rα C i = ∴ α C = a A = a C + > α C k × r CA- ω 2 C r CA =- (- 5) 2 1 j =- 25 j a B = a A + α B k × r AB- > ω 2 B r AB a B i =- 25 j + α B k × ( r AB,x i + r AB,y j ) a B i =- 25 j + α B r AB,x j- α B r AB,y i j components: =- 25 + α B r AB,x α B = 25 r AB,x 6 = 0 ∴ ω B = 0 , α B 6 = 0 . A3) Full Sphere: I C zz,S = 2 5 m S R 2 = 1 kg- m 2 1 TAM212 Hour Exam II - Spring 2005 Solution- Version B Removed Sphere: I C zz,s = 2 5 m s R 2 2 = 2 5 ρV s R 2 4 = 2 5 ρ 4 3 π R 2...
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