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Unformatted text preview: J 2000 W v m W K 2 2 1 = = → = ∆ s / m 1000 004 . 2000 2 m W 2 v = × = = No points for trying to solve this with “Favg = m a” even if getting right answer! C3 8 points Conservation of angular momentum: → ϖ = ϖ 2 2 1 1 I I s / rad 20 75 . 12 25 . 1 I I 2 1 1 2 = × = ϖ = ϖ C4 8 points WorkKinetic Energy Theorem: 2 1 1 2 1 2 2 2 2 1 I I W W K ϖϖ = → = ∆ J 60 90 150 12 25 . 1 5 . 20 75 . 5 . W 2 2 == × ×× × = C5 12 points 1D elastic collision equations (for second object initially at rest): s / m 2 4 5 . 1 5 . 5 . 1 5 . v m m m m v i 1 2 1 2 1 f 1= × += += s / m 2 4 5 . 1 5 . 5 . 2 v m m m 2 v i 1 2 1 1 f 2 + = × + × = + = C6 8 points Conservation of mechanical energy: 2 2 1 2 2 1 x k v m U K = → = ∆ + ∆ cm 00 . 4 m 0400 . 3750 5 . 1 2 k m v x = = × = =...
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 Spring '07
 Schroeder
 Physics, Energy, Kinetic Energy, Potential Energy, WorkKinetic Energy Theorem

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