Physics218sol2

# Physics218sol2 - PHYS 218 SOLUTION TO ASSIGNMENT 2 08 Feb...

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PHYS 218 - SOLUTION TO ASSIGNMENT 2 08 Feb 2008 By Chung Koo Kim and Eliot Kapit 1. A musician tuning instrument The velocity of waves along a string is given by v = T μ = (a) As both ends of the string are fixed, the wavelength is also constant. So for the musician to increase the frequency for tuning, she should increase the tension. (b) With everything else kept constant, f T or T f 2 tells us that τ c τ i = f c fi 2 = 440 435 2 1 . 023 2. Piano strings (a) For the fundamental frequency to be 261.6Hz, v = = f (2 L ) = T μ = SA ρAL/L = S ρ gives L = 1 2 f S ρ 0 . 604( m ) (b) Tension in the spring : S × A = 200 π 628( N ) Weight of a 150lb person : 150 × 0 . 453 × 9 . 8 665 . 91( N ) So the tension applied in the piano string is slightly less than, or almost as big as the weight of a 150lb person. Consequently, the total tension on the piano strings, of total number 88 × 3 = 264 (even more than this in practice)

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is the weight of mass of about 18ton! This force is enough to distort and eventually break the wooden frame of the piano.
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