tutorial13Solution

tutorial13Solution - The University of Western Australia...

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Unformatted text preview: The University of Western Australia School of Electrical, Electronic and Computer Engineering Solutions - Tutorial Sheet 13, 2006 Electromagnetic Theory ENGT 3303 Question 1 Do we have a good conductor, a good insulator or do we have to use the complicated formulas? We check the loss tangent conductor. good a be to his consider t can We 1 7 . 199 10 854 . 8 9 10 2 01 . tan 12 5 ⇒ >> = ⋅ ⋅ ⋅ ⋅ = = − π ωε σ ϑ a) 1 1 7 5 1 1 7 5 06283 . 2 01 . 10 4 10 2 06283 . 2 01 . 10 4 10 2 2 = = − = = − = ⋅ ⋅ ⋅ ⋅ = = ⋅ ⋅ ⋅ ⋅ = ≈ ≈ m rad m rad m m π π β π π α ωµσ β α m r e r 9 . 109 06283 . 9078 . 6 001 . ln 001 . = = − = ⇒ = − α α Exact values would be: [ ] ( ) [ ] ( ) 1 3 2 1 3 2 0629 . 052 . 30 10 094 . 2 1 7 . 199 2 9 2 1 tan 1 2 2 0626 . 902 . 29 10 094 . 2 1 7 . 199 2 9 2 1 tan 1 2 2 − − − − = ⋅ ⋅ = + = + + = = ⋅ ⋅ = − = − + = m c f f m c f f r r π ϑ ε ε µ π β π ϑ ε ε µ π α m r e r 3 . 110 0626 ....
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tutorial13Solution - The University of Western Australia...

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