tutorial14Solution

tutorial14Solution - The University of Western Australia...

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The University of Western Australia School of Electrical, Electronic and Computer Engineering Solutions - Tutorial Sheet 14, 2006 Electromagnetic Theory ENGT 3303 Question 1 Recall we used real fields rather than their phasor representations to calculate the Poynting vector in Lectures. Show that for propagation of an electromagnetic wave in a lossy dielectric: P ave z ()= 1 T P z , t () 0 T dt = 1 2 Re E s × H s ( ) . We are required to prove that P ave z 1 T P z , t 0 T dt = 1 2 Re E s × H s ( ) We write ( ) [ ] [] EE E E == + =+ + =− Re Re Re cos sin cos sin s jt RI ej e j t tt ωω and similarly HH H = cos sin ω . Now, ( ) ( ) ( ) [ ] P =× = × + × × + × E HEH EH RR II IR t t cos sin sin cos 22 . Since 2 1 sin 1 cos 1 0 2 0 2 = = dt t T dt t T T T and 0 cos sin 1 0 = dt t t T T ( ) PP ave T ss z T ztd t = + × 1 1 2 1 2 0 , Re
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Question 2 Derive an expression for the magnitude of the Poynting vector for uniform plane waves of arbitrary polarisations in lossless dielectrics.
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This homework help was uploaded on 04/17/2008 for the course ELEC 3305 taught by Professor - during the Spring '07 term at W. Alabama.

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tutorial14Solution - The University of Western Australia...

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