This preview shows pages 1–4. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Mechanics of Deformables Spring 2007
Homework 4 (Due Tuesday 02/130007) 4.1 The ship is pushed through the water using an A36 steel propeller shaft
that is 8 m long, measured from the propeller to the thrust bearing D at the
engine. If it has an outer diameter of 400 mm and a wall thickness of 50 mm,
determine the amount of axial contraction of the shaft when the propeller
exerts a force on the shaft of 5 kN. The bearings at B and C are journal
bearings. 17 #30 kN
H ——>
5' KN ‘
R
S __ FL .5.0 (log) __ ﬂ 2: f
a E Tr (0.4i—1'r03L) (202))“
+%: (l0)
#6)”.
 r 3.63800 7.  3 6+ (to #3)“ Z — V1 Means WOJQS "1th Nels D  4.2 The A—36 steel column is used to support the symmetric loads from the
two ﬂoors of a building. Determine the vertical displacement of its top A if
P1 = 40 kip, P2 = 62 kip, and the column has a cross—sectional area of 23.4
 2
1n . K
S=ZPL
13 E 1' agoo ((2)020
93+c29o)“°3) U“? \L it») w? .1— (— 20‘?) (l1)(l2.] Q‘Ic 
~93 ‘H 003)) 62 ,1, 62 WP \h‘ 1’ k‘P “230*,de S {UM
Moms 9
W‘s,qu dowoi’ds C. 4.3 The post is made of Douglas ﬁr and has a diameter of 60 m. If it is
subjected to the load of 20 kN and the soil provides a frictional resistance
that is uniformly distributed along its sides of w = 4 kN/m, determine the
force F at its bottom needed for equilibrium. Also, what is the displacement
of the top of the post A with respect to its bottom B? Neglect the weight of
the post. T’sr’ce.
TFF.5 = , $30“;
F+6'0020=O "
F” lQo kid 3‘“ $20 “4
BN5 4(1)
= 80
KN . j
. ‘ti
D‘s IMOWent
E L __
r:
gens: j 11;) 9s \i/
0 mpg Fiﬁ)
2—H
: _l.. [(43,20'Jc1}
HE 0 Linn
'” _‘ (ag‘rﬂzogﬂo
PIE 3 7 #‘8ét1
~ * 32 W m .w m 4.4 The assembly consists of two A—36 steel suspender rods AC and BD
attached to the 100lb uniform rigid beam AB. Determine the position x for
the 300—lb loading so that the beam remains in a horizontal position both
before and after the load is applied. Each rod has a diameter of 0.5 in. =r———— Bum—4 +23!“ 2 0‘. Flat”)  30th  100(15) = 0 + 2M. :2 0; F:4c(30) + MSO—x} + 10005} I: 0 ﬁc  350 — 10:: {2)
54 I 8’
From Eq. (1) and (2). (350  10:)(15) = (10: + 50x25)
.415 u: A 3 (5"
5250111: = 250.: + 1250 molt x 10m Ans ...
View Full
Document
 Spring '07
 Speich

Click to edit the document details