HW-4Solutions-01-09-08

HW-4Solutions-01-09-08 - Physics 21 Spring 2008 HW-4...

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Physics 21 Spring 2008 January 9, 2008 H W - 4 S o l u t i o n s 4-1 (HRW 23-4) At each point on the surface of the cube shown in Fig. 23-27, the electric field is parallel to the z axis. The length of each edge of the cube is 3m. On the top face of the cube , and on the bottom face . Determine the net charge contained within the cube. Figure 23-27 Solution: There is no flux through the sides, so we have two “inward” contributions to the flux, one from the top (of magnitude (34)(3.0) 2 ) and one from the bottom (of magnitude (20)(3.0) 2 ). With “inward” flux being negative, the result is Φ = – 486 N m 2 /C. Gauss’ law then leads to 12 2 2 2 9 enc 0 (8.85 10 C /N m )( 486 N m C) 4.3 10 C. q ε −− = × = − × 4-2 (HRW 23-17) Space vehicles traveling through Earth's radiation belts can intercept a significant number of electrons. The resulting charge buildup can damage electronic components and disrupt operations. Suppose a spherical metal satellite in diameter accumulates
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This note was uploaded on 02/20/2008 for the course PHYSIC 2 taught by Professor Kim during the Spring '08 term at Lehigh University .

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HW-4Solutions-01-09-08 - Physics 21 Spring 2008 HW-4...

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