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Unformatted text preview: answer, just write the correct algebraic equation.) n=PV/RT 3. If the amount of gas (in grams) is known, the molecular weight of a gas can be determined. (Recall how molecular weights are needed for determining molecular formulas knowing empirical formulas.) You have 15 grams of a gaseous unknown substance. If the substance has a volume of 11.2 liters at a pressure of 1 atmosphere and a temperature of 0 O C, determine the molecular weight of this unknown substance. (HINT: You will need the equation from #2 above and the units of molecular weight. Use dimensional analysis!) Try to use correct significant figures. n=?=.5moles (1 atm *11.2 liter )/[.08205(( liter * atm )/(mole* K ))]*(273 K )=.5moles...
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This note was uploaded on 04/18/2008 for the course CHEM 1151L taught by Professor Stone during the Spring '08 term at Clayton.
 Spring '08
 STONE
 pH

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