- –(aq K neutral CN – weak base K b = K w/K a(HCN = 2.0·10 –5 NH 4 Cl 1.1·10 –5 9.4·10 –10 or 9.1·10 –10 4.98 or 4.96 9.02 or 9.04

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0.20 M [H + ] or [H 3 O + ] [OH ] pH pOH Reaction Equation(s) (and additional information) HNO 3 0.20 5.0·10 –14 0.70 13.3 HNO 3 (aq) + H 2 O (l) NO 3 (aq) + H 3 O + (aq) Strong acid, assume complete dissociation KOH 5.0·10 –14 0.20 13.3 0.70 KOH (s) K + (aq) + OH (aq) Strong base, assume complete dissociation NH 3 5.3·10 –12 1.9·10 –3 11.28 2.72 NH 3 (aq) + H 2 O (l) NH 4 + (aq) + OH (aq) Weak base, K b = 1.8·10 –5 HC 2 H 3 O 2 or CH 3 COOH 1.9·10 –3 5.3·10 –12 2.72 11.28 CH 3 COOH (aq) + H 2 O (l) CH 3 COO (aq) + H 3 O + (aq) Weak acid, K a = 1.8·10 –5 HF 8.2·10 –3 1.2·10 –12 2.09 11.91 HF (aq) + H 2 O (l) F (aq) + H 3 O + (aq) Weak acid with large K a , K a = 3.5·10 –4 NaCl 1.0·10 –7 1.0·10 –7 7.00 7.00 NaCl (s) Na + (aq) + Cl (aq) Neutral salt, assume complete dissociation KCN 5.0·10 –12 2.0·10 –3 11.30 2.70 KCN (s) K + (aq) + CN (aq) CN (aq) + H 2 O (l) HCN (aq) + OH
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Unformatted text preview: – (aq) K + neutral, CN – weak base, K b = K w /K a (HCN) = 2.0·10 –5 NH 4 Cl 1.1·10 –5 9.4·10 –10 or 9.1·10 –10 4.98 or 4.96 9.02 or 9.04 NH 4 Cl (s) NH 4 + (aq) + Cl – (aq) NH 4 + (aq) + H 2 O (l) NH 3 (aq) + H 3 O + (aq) Cl – neutral, NH 4 + Weak acid, K a = K w /K b (NH 3 ) = 5.6·10 –10 H 3 AsO 4 3.1·10 –2 3.2·10 –13 1.51 12.49 H 3 AsO 4 (aq) + H 2 O (l) H 2 AsO 4 – (aq) + H 3 O + (aq) K a = 5.6·10 –3 H 2 AsO 4 – (aq) + H 2 O (l) HAsO 4 2– (aq) + H 3 O + (aq) K a = 1.7·10 –7 HAsO 4 2– (aq) + H 2 O (l) AsO 4 3– (aq) + H 3 O + (aq) K a = 4.0·10 –12 Ca(OH) 2 2.5·10 –14 0.40 13.60 0.40 Ca(OH) 2 (s) → Ca 2+ (aq) + 2 OH – (aq) Strong base, assume complete dissociation...
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This note was uploaded on 04/17/2008 for the course CHEM 121b taught by Professor Wiediger during the Spring '08 term at Southern Illinois University Edwardsville.

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