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Unformatted text preview: / KB] CHI“ 1045 Exam 3
Section # 0107
November 07, 2007 Wednesday
Total points: 100 Time: 45 minutes This EXAM contains 3 questions. A periodic table is provided at the back of this exam. The
equations for numerical calculations, conversion factors, and the values of constants are provided w}: ere necessaly.
SHO WALL YOUR WORK WHEN YOU ARE SOL WNG NUMERICAL PROBLEMS TO GET THE FULL CREDIT. l. a. The enthalpy changes for the following reactions can be measured: H202U) ———) H20U) + 12? 02(g); AH" =  98.0 k] ....... ..(1)
2H2(g)+ 02(3)  ~—) 2 H200); ° = 571.6 M ....... ..(2)
i) Show how you can delive the following equation by using equations (1) and (2): [8] Hz(g) + 02(3) H2020); AH” = unknown (3) new}; 3H2 + O? "_’ 2 4H2 0‘ 4 is“) 1»: 4,2”; + 20.1 —_—> 2H202. 2' “3
\Ir 0‘
§ .\ .
xx go '5? + Continued to page 2
do I OX 1 ii) Use the enthalpy values of equation (I) and (2) and Hess’s Law to derive an equation \
which can be used to calculate the enthalpy change for the reaction: [7] H2(g) + 02(g) —) H202U); AH" = unknown (3) — 24H1 + 4H2 .. 24H3 AH :l AH  AH]
3 2. 2 1 iii) Use the equation derived in the previous question 1a(ii) to calculate the enthalpy change
for the reaction: [5] Hztg) + 02(3) ""9 H2020); AH" ZUDkIIOWD   (3)
ans = a Egypt. — 2(— 389 .— l   ' G _ a E 5m 6 + ‘1] :: —— IB}'8 k3 iv) Draw an enthalpy level diagram that shows the relationship between the energy
quantities involved among the three [(1), (2) and (3)] equations. [10] _. 24111 + de = 249:3 AH 24m \ 2 49. SM" = 2
2 7'  5 __ 1' . ml
J54“: = :ka EQ‘J‘ W2 ? 6MP“ ::9;)'~3 Bilem“
.1: 9 14ml _ 2x—98'0k3 ————'————
Continued to page 3 2 2. a. Determine the ‘nH’ values of the following orbitals and then compare the order of energy of the three orbital (lowest, highest or intermediate): [3 x (2+2) = 12]
n + I value Ener lowestfhi estfintermediatc
3p 3 + I = A ‘ 003 M + 45 4+0 = 4 iniwmeAia’re. 3d 3+2 =S' ﬁght/3* b. Write down the electron conﬁguration of the following atomsfelements using 'orbz‘tal box
notation’: [4 x 2 = 8] ,7. t on m E m
or} ‘ Kg 1": 25 2 P 3 3 a
b P (15):
93,; ED N [E t
I 5( ‘4 IS 15
e 0" a‘ 0. Write down the electron conﬁguration of the following element by using ‘spdfnotatz’on' or w 'noble gas notation’. [3 x 2 = 6] Ni(28): [A151 34245,, 0"", Dirt] 461 3698 {31(17): [N 2.1" 3523f); d. Identify the atomsfelements which have following electron conﬁguration: [4 >< 3 = 12]
[Ne] 352 3p' : Al
0
[Ar] 3d2 452 : Ti _
[Xe] 6s2 : ' Bo“
Continued to page 4 3 6. Identify the elements of the following groups as 5, p, d— and f1 block elements: [2 x 3 = 6] Group 1A elements: 8 "' ‘3 lock Group 7A elements: A
Group SB elements: d "' 06K 3. 3. Give the n, land all possible m; values for 4forbitals. [1 + 2 + 5 = 8] 51 y I: Q MM" gill.» Email—W “'2 "l 0 “I “H” 3 t a?» at
0*q‘f‘x ’ . Identify the orbital with the following set of quantum numbers: [2 x 2 = 4] n=3,l=1,m,r=+l: n=4,l=2,ml=+2: c. What are the possible values of m; for I = 2. [5] ml: 2L 0, +1, +1 I d. Draw the shapes of the s and p; orbital. (you must show the Cartesian axes and axis label properly in ygr drawing to get the credit). 2. [4]
+9»
“0 o~®D§wB i ‘K
t“ 33
s 0"
D
TContfn ued to page 5
‘I 4
\ PX S—ofbi‘l'ﬁ l/ e. Calculate the wavelength, in nanometers, associated with a proton traveling at a speed of 2.55 x 106 111. 3'1. Use 1.67 x IO‘I’r kg as the proton mass. [5]
7‘ 'm v No porL" " 5“ [Equation: 1 = h 1 mv; Planck's constant, h = 6.626 x 10'34 1.5; 1 J = 1 kg. 1112152; 1 11m = 1 1
11m = 1 x 10'9 [11] End of Exam Electmn Conﬁgurations and Chemical Perioc 3d——— 3p——— 33—Samen+£, ' 8.3 Marni: Subsbell Enargies and Etnahon Assignments ...
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