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Unformatted text preview: Mi >=0 i=1,,3 Xij>=0 i=1,,3 j=1,,4 3. Let (all variables are in ounces) Ing. 1 = Sugar, Ing. 2 = Nuts, Ing. 3 = Chocolate, Candy 1 = Slugger and Candy 2 = Easy Out Let x ij = Ounces of Ing. i used to make candy j. The appropriate LP is max z = 25(x 12 + x 22 + x 32 ) + 20(x 11 + x 21 + x 31 ) s.t. x 11 + x 12 100 (Sugar Const.) x 21 + x 22 20 (Nuts Constraint) x 31 + x 32 30 (Chocolate Const.) .8x 22.2x 12.2x 32 0 .9x 21.1x 11.1x 31 0 .9x 31.1x 11.1x 21 0 x ij 0 i=1,,3 j=1,,2 4. xij = barrels of oil i used to make product j (j = 1 is gasoline and j = 2 is heating oil) ai = dollars spent advertising product i max z = 25(x11 + x21) + 20(x12 + x22)  a1  a2 s.t. x11 + x21 = 5a1 x12 + x22 = 10a2 2x11  3x21 0 x11 + x12 5,000 x21 + x22 10,000 4x12  x22 0 xij 0 i=1,2 j=1,2...
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 Spring '08
 JuanPabloVielma
 Optimization

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