Unformatted text preview: Equating (2) with (3) cm cm cm s cm j i j i 1 1 2 8 15 25 / 30 ω − ω − = ω − − looking just at the xcomponents gives us k s rad s rad cm s cm / 2 / 2 15 / 30 1 1 1 = ω ⇒ = ω ⇒ ω − = − v looking just at the ycomponents gives us k s rad s rad s rad x cm cm / 64 . / 64 . / 2 8 25 8 25 2 2 2 1 2 = ω ⇒ = ω ⇒ = ω ⇒ ω − = ω − v 3.12 Done in class 3.14 Given: The wheel has an angular velocity of 2 rad/s k , and the v c = 0.3m/s i . Find: v A Solution: ( ) ( ) ( ) cm m CA j i r 13 / 5 13 / 12 48 . + = The “2point” formula gives ( ) ( ) ( ) ( ) s m AC C A / 13 / 5 13 / 12 48 . 2 3 . j i k i r v v + × − + − = × ω + = v i.e., ( ) ( ) ( ) [ ] ( ) s m s m A / 886 . 069 . / 13 / 5 13 / 12 96 . 3 . j i i j i v − = + − + − = A B O C k i j k i j...
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This note was uploaded on 04/18/2008 for the course TAM 212 taught by Professor Keane during the Spring '08 term at University of Illinois at Urbana–Champaign.
 Spring '08
 Keane

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