CHE222_solutions7

CHE222_solutions7 - ChE 222: Problem Set #7 Due: March...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
ChE 222: Problem Set #7 Due: March 14,2008 (8:OO am) (9) 1 .) Koretsky, Problem 2.52 ( 3Y ) 2.) Felder and Rousseau, Problem 9.12 c ao) 3 Felder and Rousseau, Problem 9.14
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
2.52 A mass balance shows To develop the energy balance, neglect kinetic and potential energy. Also, no shaft work is performed, so the energy balance becomes The energy balance can be expanded to If the reference state is set to be liquid propane at 0 OC and 4.68 bar, the internal energies become Once the change in internal energy for vaporization and temperature of state 2 is determined, Q can be solved. As the liquid evaporates, the pressure increases. At state 2, where saturated propane vapor is present, the ideal gas law states 1 To find v2, assume that v; >> vl . The volume of the rigid container is Therefore,
Background image of page 2
Also, since the propane is saturated, P2 and T2 are not independent of each other. They are related through the Antoine Equation, where pSat = P2 and T Sat = T2 Substitution provides, Using values from Table A. I. 1 and R = 8.3 14 x 10- To find Auvap, refer to the definition of enthalpy.
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 14

CHE222_solutions7 - ChE 222: Problem Set #7 Due: March...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online