Lecture13_S08 - Feb 18 2008 Lecture 13 Chapter 16 Acids and...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Feb. 18, 2008 Lecture 13, Chapter 16: Acids and Bases http://genchem.chem.wisc.edu/demonstrati ons/Gen_Chem_Pages/14acidpage/acidm ain.htm 1 M HCl (aq) + Na 2 CO 3 (s) 1 M H(OAc) (aq) + Na 2 CO 3 (s) Mg o (s) + 2 HX (aq) MgX 2 (aq) + H 2 (g) In the above left case: 2 H + (aq) + 2X - (aq) + Na 2 CO 3 (s) 2 HX 2 NaX + H CO CO 2 (g) + H 2 O (l) (aq) (aq) + H 2 CO 3 (aq) Several lessons can be extracted from the above experiments but we will focus on two: - Reactions typically occur in the direction to form weaker acids (or bases) - Rate of the above reactions depend on the strength of acids, The more dissociated the acid, the stronger the acid, the faster the reaction Measure relative acid strength by either K a ’s or pK a ’s H + (aq) + X - (aq) HX (aq) K a = [H+][X-] [HA] Acid dissociation constant Conjugate base of weak acid HX Is a fairly decent (but not strong) base, It can pull a proton off water or H 3 O + to reform some of the acid so, the equilibrium usually lies to the left for a weak acid, therefore K a is small pK a = -log K a smaller pKa = larger K a = more dissociated pK a K a = 10 -pKa 0
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern