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Discussion4

# Discussion4 - Discussion 4 Chem002 Spring 2008[1 The...

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Discussion 4 Chem002 Spring 2008 [1] The reaction below is first order in 2 2 [H O ] : 2 2 2 2 2H O (l) 2H O (l) + O (g) A solution originally at 0.600 M 2 2 H O is found to be 0.075 M after 54 min. The half-life for this reaction is __________ min. A) 6.8 B) 18 C) 14 D) 28 E) 54 [2] For the following reaction: 2 BrO 2 + 2 NaOH → NaBrO 3 + NaBrO 2 + H 2 O (a) Find the rate law (b) find the rate constant [3] Given the plots obtained for the theological reaction: good→ evil: (a) Give the rate law for the reaction. (b) If the half life of the reaction is 500 s, what is the rate constant, k? What is the concentration of evil ([evil]!!!) after 110 s of initial reaction. Three trials were run: [BrO 2 ] [NaOH] rate (M/s) 0.18 0.09 0.123 0.06 0.09 0.0137 0.06 0.18 0.0274

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[4] The following mechanism has been proposed: (a) What is the net chemical equation (b) identify intermediates, if any. (c) What rate law is predicted by this proposed mechanism? Show any work. (a) net chemical equation: (b) intermediates: (c) rate law: (d) If the average rate constant is 2.70x10 -4 M -1 s -1 at 600 K and 3.50x10 -3 M -1 s -1 at 650 K. Find the activation energy, E a in kJ/mol.
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Discussion4 - Discussion 4 Chem002 Spring 2008[1 The...

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