PH2014_ES_CH_11_12

# PH2014_ES_CH_11_12 - 11.15 A 500 g particle moving along...

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Unformatted text preview: 11.15 A 500 g particle moving along the x-axis experiences the force shown below. The particle goes from v x = 2 . 0 m/s at x = 0 m to v x = 6 . 0 m/s at x = 2 m. What is F max ? By the Work-Kinetic energy theorem we know that W = Δ KE . To find the Work done on the particle in this problem we can simply take the area under the curve. If we then equate that to the change in Kinetic Energy we can solve for F max . The area under the curve is the area of the triangle with Base of 2 m and Height of F max . So we have: W = Δ KE 1 2 base * height = 1 2 mv 2 f- 1 2 mv 2 o 1 2 F max * 2 m = 1 2 . 5kg((6m / s) 2- (2m / s) 2 ) F max = 8 N 11.42 Sam, whose mass is 75 kg straps on his skis and starts down a 50-m-high, 20 ◦ frictionless slope. A strong headwind exerts a horizontal force of 200 N on him as he skis. Find Sam’s speed at the bottom (a) using work and energy, (b) using Newton’s laws....
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## This homework help was uploaded on 04/17/2008 for the course PHYS 2014 taught by Professor Nandi during the Spring '08 term at Oklahoma State.

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PH2014_ES_CH_11_12 - 11.15 A 500 g particle moving along...

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