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Unformatted text preview: d ~ H = Id ~ l ( ~ r~ r ) 4  ~ r~ r  3 [ A/m ] (3) (a) Solve for the magnetic eld intensity vector ~ H at point P (0 , , z ) if the current I ows along the path shown in Figure 2. (i.e. the path is a quarter of a circle where = a ). (b) Solve for ~ H , if the same geometry as in (2a), the current path is half a circle (from = 0 to = ). 1 x y z L r = 2S 3 z = 3 S 2 S 1 Figure 1: A close path and surfaces (c) Solve for ~ H , if the current path form a complete circle. (Do not omit any component due to symmetry arguments when calculating the solution.) x y z P(0,0,z) a z' a a Idl Figure 2: Current I 2...
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This note was uploaded on 04/17/2008 for the course ELE 401 taught by Professor Forgot during the Spring '08 term at Ryerson.
 Spring '08
 forgot

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