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Unformatted text preview: d ~ H = Id ~ l × ( ~ r-~ r ) 4 π | ~ r-~ r | 3 [ A/m ] (3) (a) Solve for the magnetic ﬁeld intensity vector ~ H at point P (0 , , z ) if the current I ﬂows along the path shown in Figure 2. (i.e. the path is a quarter of a circle where ρ = a ). (b) Solve for ~ H , if the same geometry as in (2a), the current path is half a circle (from φ = 0 to φ = π ). 1 x y z L r = 2-S 3 z = 3 S 2 S 1 Figure 1: A close path and surfaces (c) Solve for ~ H , if the current path form a complete circle. (Do not omit any component due to symmetry arguments when calculating the solution.) x y z P(0,0,z) a z' a a Idl Figure 2: Current I 2...
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- Spring '08
- Magnetic Field, 3 L, close path, current path form