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Unformatted text preview: PHYS408 Fall 2008 Mastering Physics Assignment #7 Solutions Problem 21.11 A 121cmlong, 4.0 g string oscillates in its m =3 mode with a frequency of 180 Hz and a maximum amplitude of 5.0 mm. (a) What is the wavelength in the string? The first mode for the string would be a halfwavelength. The third mode would be 3/2 wavelengths. So 3 2 λ = L λ = 2 3 L = 2 3 121 cm ( ) = 80.7 cm = 0.8067 m (b) What is the tension in the string? The tension is related to the mass density and velocity: v = T s μ The velocity relates to the wavelength and frequency, which are known. v = λ f = 0.8067 m ( ) 180 Hz ( ) = 145.2 m / s The linear density is μ = 4.0 g 121 cm = 4.0 × 10 − 3 kg 1.21 m = 3.306 × 10 − 3 kg / m So T s = μ v 2 = 3.306 × 10 − 3 kg / m ( ) 145.2 m / s ( ) 2 = 69.7 N Problem 21.12 A heavy piece of hanging sculpture is suspended by a 90cmlong, 5.0 g steel wire. When the wind blows hard, the wire hums at its fundamental frequency of 80 Hz....
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 Spring '08
 BEANE
 Physics, 2.00 m, 1.20 m, 1.80 m, 1.90 m, 0.400kg

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