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# 7.4-5 - Pruhlsm 7.4-5 An element in Mancini stress is...

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Unformatted text preview: Pruhlsm 7.4-5 An element in Mancini stress is subjected to stresses ‘3? crx = sum psi and or}1 = —1500 psi, as shown in ﬁre ﬁgure. Using Mohr’s circle, determine (a) the stresses acting on an element J 15E!) psi oriented at a counterclockwise angle ti = ﬁﬂ“ from the .1: axis and (b) the maximum shear stresses and associated normal stresses. Show all results on sketches of properly.r oriented elements. mpsi 1‘— D —h- Snlutlnn 14-5 BiaJdal stress o'x= ﬁﬂﬂﬂpsi nr= —15[}ﬂpsi Trey: [It {a} ELEMENT AT ti = ﬁﬂ" {All stresses in psi] 23 = 120° 9 = tiﬂ” 211' = T501) psi R = 3760 psi Point C: ”xi = 225!) psi Paint D: :le = 2250 — F. 420560“ = 375 psi {b} NIAXIMIJM SHEAR STRESSES Tm. = —R sinﬁﬂ“ = —3248 psi Point 5.1: 23" = —9IJ'° 9.1. = _45.:. Point 3': an = 225D + R c0560“ = 4125 psi Tm“ = R = STSD psi Tm = R sin 60° = 3243 psi Paint 5'2: 233: = 9D“ [4,! = 45° rmﬂ = —R = —3T5ﬂ psi an“: = 2250' psi ...
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