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7.4-8 - Solution 14-3 Pure shear fl=D cr=D 1...

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Unformatted text preview: Solution 14-3 Pure shear fl=D cr=D 1' =—lfihrilPa I :r I? {a} HEHEHT AT t3 = 11]“ {All stresses in MPH} 2fi=4fl° fl=2fl° R=lfiMPa Origin 0 is at center of circle. Paint P1: is“ = 2TH“ Hm = 135” {fl = R = 16 MPH Point P3: 2:19PI = 91]” HP: = 45° —R = —16 MFn q M II Pm'nt D: (In = —R si.112lraL = —lfl'.23 MP3 TIL“ = —R ens 219 = — 12.26 We Pm'mD': ”—1-. = R siJ12-H = 111.28 MPH TIL“ = E 013529 =12.2fi MP3 ...
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