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Unformatted text preview: Tong Huang ECE314 Spring 2007 Assignment 3 1. a) Assume drawing cards without replacements. The probability of drawing all 4 aces with 4 cards is 4 52 * 3 51 * 2 50 * 1 49 = 24 6497400 = 3.693785 *10 6 . We are drawing 5 cards, therefore there are 5 choose 4 ways for the aces to show up. So the answer is 3.693785 *106 5 4 = 1.846892 105 b) Assume drawing cards without replacements. The probability of drawing 4 of a kind with 4 cards is 3 51 * 2 50 * 1 49 = 4.801921 105 . We are drawing 5 cards, therefore there are 5 choose 4 ways to arrange these 4 cards. The answer is 4.801921*105 5 4 = 2.400960 104 c) Assume drawing cards without replacements. The probability of drawing at least 3 aces 4 3 49 2 52 5 = 0.00181 d) Assume drawing cards without replacements. The probability of drawing exactly 3 of a kind is 3 51 * 2 50 * 48 49 * 47 48 * 5 3 = 0.022569 2. There are 21 consonants and 5 vowels. a) Duplicates are allowed. This means replacement is allowed. The probability that { C 1 , C 2 , C 3 } contains exactly one vowel is 5 26 * 21 26 * 21 26 * 3 2 = 0.3764 .....
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This homework help was uploaded on 04/18/2008 for the course ECE 314 taught by Professor Idk during the Spring '07 term at UMass (Amherst).
 Spring '07
 idk

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