ECE314hw4 - Tong Huang ECE314 spring 2997 Homework 4 0.3 y...

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Tong Huang ECE314 spring 2997 Homework 4 1. a) P Y ( y ) = 0.3 ψ = 0 0.05 ψ = 1 0.15 ψ = 2 0.1 ψ = 3 0.4 ψ = 4 0 οτηερϖισε ° ° ° ° ° ° b) According to the CDF given, 35% of students score 1 or less, and 50% of students score 2 or less. We have to made the passing probability as close to 0.6 as possible but not greater than 0.6. Therefore the passing grade will be 2. c) 50% passed the quiz and 40% got A, P ({grade is “A”}|{passing grade}) =.4/.5=.8 2. F X ( x ) = 0.07 υ ( ξ 29 + 0.08 υ ( ξ -1 29 + 0.25 υ ( ξ - 229 + 0.1 υ ( ξ - 3 29 + 0.2 υ ( ξ - 429 + 0.3 υ ( ξ - 529 F Y ( y ) = 0.2 υ ( ψ 29 + 0.3 υ ( ψ -1 29 + 0.2 υ ( ψ - 229 + 0.15 υ ( ψ - 3 29 + 0.1 υ ( ψ - 429 + 0.05 υ ( ψ - 529 u ( x ) = 0 ξ < 0 1 ξ 0 a) P X ( x ) = 0.07 ξ = 0 0.08 ξ = 1 0.25 ξ = 2 0.1 ξ = 3 0.2 ξ = 4 0.3 ξ = 5 0 οτηερϖισε ° ° ° ° ° ° ° ° P Y ( y ) = 0.2 ψ = 0 0.3 ψ = 1 0.2 ψ = 2 0.15 ψ = 3 0.1 ψ = 4 0.05 ψ = 5 0 οτηερϖισε ° ° ° ° ° ° ° ° b) F X (3) = 0.07 υ (3 29 + 0.08 υ (229 + 0.25 υ (1 29 + 0.1 υ (029 + 0.2 υ (-1 29 + 0.3 υ (-229 = 0.5 c) Given the shipment have at least 2 bad chips, find the probability that the number of bad chips in the shipment is less than or equal to 3.
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