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key42_le2_sprg07

# key42_le2_sprg07 - ECE 3042 Lecture Exam No 2 Spring 2007 V...

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Unformatted text preview: ECE 3042 Lecture Exam No. 2 Spring 2007 V THURSDAY, APRIL 5, 2007, 6—7 PM STUDENT N . Name Closed Book and Note. Calculator Permitted. Four Equ 1y Weighted Prob- lems. All Work Must Be Shown for Credit. Box All Answers. ﬂ 3, 3 1. A certain op amp active ﬁlter has the complex transfer function ii _ Q W0 ﬂ : ; M ’ T(s) — K —— A -" 7 + 3.2 li+1 (2 H [‘14: Hé we Where K 2 12, Q = 7, and f0 = 3.23 kHz. What is ,3 gm, TM 0 The order of the ﬁlter? 2 Emma/PW o The type of ﬁlter? \_ 06’ o The dc gain in dB? 0 The half power bandwidth in Hertz? L1 6 I 2 o The gain in dB when f = 5kHz? V _ 90 o The inﬁnite frequency gain in dB? 2. Shown below are the output and transfer characteristics for a particular NPN BJ T. Assume that the thermal voltage is 26 mV. Output Characteristic 3.510“ 3104 2.510a o 4 E 2 8 a 1.5m a E = 3 r = r = ‘3 3 : 1 : , : 3 010° : .5104 L a i _a__ ; i - 0 2 4 6 B 10 12 ColleaoNo-Eumngolhge 510“1 Tmnsfor Chracteristic 41a“ “04 . 010° § 2 ; Am1 I _i_ i i -o.2 o 02 0.4 (M 0.3 Base-to-ErriuorVonlge The following three data points are taken from the output characteristic (I 13, V03, I C): (20pA, 1 V, 3.0077 mA), (ZOHA, 5 V, 3.1675 mA), (203A, 9 V, 3.3274 mA). A single data point is taken from the transfer characteristic (VBE, Ia, VCE) : (0.699894 V, 597.484/lA, 5 V). From this data determine: 7‘1, 252 \/ 6 The Early voltage (0753 g The zero bias forward current ratio l 11 3 ' 3 g [1 6 The zero bias saturation current [50; 377, ‘(8‘1 X10" M. l + “2..., 77,261 H l,1*llng;/I ll 3. Shown below is an NMOS INVERTER with resistive load. V+ NMOS INVERTER with Resistive Load The power supply is V+ = 20 V and the resistor RD 2 50 k9. The parameter for the N Channel Enhancement Mode MOSFET are: K = 300pA/V2, VT 2 1.5 V, and A = 0. Determine for this inverter LR VOL: 35:... : 0:667V 311R VOH: V .L—a: 1.533V C(VIL VT + ZlTR W I _— 2.8V VIE: VT +2 Z/rFR arr/2 H Li W 4. Shown below is an op amp active ﬁlter. Assume that the op amp is ideal. C) What is the linear dc gain? O What is the linear inﬁnite frequency gain? N0 N0 Could this be a low pass ﬁlter? Could this be a high pass ﬁlter? Derive the complex transfer function T(s) = VL/Vi. - f” 7‘ ’T C ' r<‘\7'_\7>“'—Y_+(~‘/°’I/:O / ’@ x. L R \' if.) "‘TIJ r 6‘ r< ’ '— \7 A RC 4—! : if 0 WO __ 0 ~ — ﬂ ._ - Azn¢+2ali¢ (\$44.1- Her ,m/ m 1.533 6.667 A .— (- ECE 3042 Formula Sheet IC 6 _ IE, I _ Ic exp ‘VBE 3 0- so‘ = VCE VCE VT E mc 1+— 1+— _1 1 4VDD —:I: + RK KR 2 2 V _ RK vi=v0+vT F=\/Ea ° 2 F=q(E®v®B) c2=a3+b4 F=kx3 R” [email protected]"; i V I U 1 1 4 ’ Vi=VT+—- VO=VDD—— e: (1+h)h —6 2KR 4KR h—>0 3(ID K: 20/) V v _ 2 _ dS ‘f‘T— " / ID—K(Vgs- VT) ID”2 vgs_VT_ T VdS [email protected];:Z’g 0 3KR 1 T 3KR 2KR 111(6)=1 K0 K=W VT=VTO+7(\/VSB+2¢F_2J¢F) sinze + c0329 = 1 sin29 = 25in6c059 -t Vc(t) = Vc(oo) — (Vc(oo) — Vc(0))e T T = RC A m=_y Ax 5 y=mx+b °c=;(°F—32) ECE 3042 Lecture Exam No. 2 Spring 2007 FRIDAY, APRIL 6, 2007, 2-3 PM STUDENT No. Name Closed Book and Note. Calculator Permitted. Four qually Weighted Prob- lems. All Work Must Be Shown for Credit. Box All Answers. ‘ 1. A certain op amp active ﬁlter has the complex transfer function (-92“ a4: {412W “0 T(s) = K 2 s 1 a +530“ where K = 15, Q = 7, and f0 = 7.77 kHz. What is W/ T m j o The order of the ﬁlter? 8 ) 5 ' T N “252% o The type of ﬁlter? o The dc gain in dB? / 3" ‘-\ ., I ? \ «M I o The inﬁnite frequency gain in dB (5 3 0 The half power bandwidth in Hertz? l ’ ’ 5/ 9 \s. y o The phase shift in degrees when f 2 10kHz? N TM»): \5 \ ‘77 2. Shown below are the output and transfer characteristics for a particular NPN BJ T. Assume that the thermal voltage is 26 mV. ‘3um Chﬁr.¢‘“hﬁc Transfer Characteristic 2.510”1 r _r— _r _r- r- _r [410'2 ! 7 1 r 2104 _.. V 11g! A . 1.51m1 1 , E _ Ema g E 8 5 3 110’ ,5 “on g ‘8 ll 3 S o E 0 410‘" 510‘ : : ; 210J a ma 010“ .510‘ i l— L i i _zwa i i L i _. 2 0 2 4 8 8 10 12 -0.2 0 DZ 04 06 08 Colleciar-(o-Em‘nmr Voltage Base-lo-Emilter Vohge The following three data points are taken from the output characteristic (I B, V03, [0): (2mm, 1 V, 2.0094 mA), (20%, 5 V, 2.1362 mA), (20%, 9 V, 2.263 mA). A single data point is taken from the transfer characteristic (VBEJC, VCE) : (0.7 V, 1.8186mA, 5 V). From this data determine: 2 0 W g The Early voltage Q 2 ' 7 \/ g The zero bias forward current ratio a] 8’ ’ C7 5 3'Lﬂggg :3,“/Z%/0 H The zero bias saturation current 2254,00?” 2,1362‘0 ,vnzéwgi .3 M C/ v) 3 + M 2,136 ZWD‘3 _ 1'3- ﬂ"- ox 2,3 (9 - “7W ’ 7 a )8 ﬁts/6qu l6 26” w ’ Lao“: WE"; Mi” 3. Shown below is an NMOS INVERTER with resistive load. V+ NMOS INVERTER with Resistive Load The power supply is VJr = 15 V and the resistor RD 2 50 k9. The parameter for the N Channel Enhancement Mode MOSFET are: K = 400pA/V2, VT 2 1 V, and A = 0. Determine for this inverter The boundary (on the voltage transfer characteristic) between the cutoff and saturation region for the MOSFET \W Li v]: ‘V ’7 The boundary (on the voltage transfer characteristic) between the saturation and triode region for the MOSFET 0,%"ll\/ L). V0: l < l l 4.. Shown below is an op amp active ﬁlter. Assume that the op amp is ideal. What is the linear dc gain? What is the linear inﬁnite frequency gain? 7% “7‘ Could this be a low pass ﬁlter? Could this be a high pass ﬁlter? N 0 b1 Derive the complex transfer function T (s) = Vo/Vi. JV ' "‘ <7 + VDVV,» 5‘ " ,. Ha L Z \-/ + AC. \/(J —— O , 70 I M w a ‘ "17‘" :47; m / T7 / 4".["”c”~‘3/JPC" "'w aha! 0mm LW/ Pow/l 4 F=q(E€Bv®B) 1 V-=V +—— 1 T 2KR ID = K(Vgs — VT)2 VDD v0 = —— 3KR K = ._—K(.)._ sin26 + cos26 = 1 Vc(t) = Vc(oo) — (Vc(oo) — Vc(0))e T y=mx+b ECE 3042 Formula Sheet Ic exp 'VBE 3 E=mc "6 V v 54 MD I A H f" ‘/ . «w “/r A ~ ~ ’ L VDD n? [5 a “:0 . ,r‘. #1.. Vi=Vo+VT F=\/Ea « 25.641 c2=a3+b4 F=kx3 v—V ; e— um M)? 0 DD 4KR h—>0 __ Vds ID’2 Vgs_vT'T Vds VDD 1 Vi=VT+2 ———— 3KR 2KR vT = VTO + q( (VSB + 2¢F — 2 ¢F) 1n(e) = 1 sin26 = 2sinecose —t T=RC m=ﬂ 5 °C=— °F—32 Ax 9( ) ...
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