finalCME

finalCME - 1 You have a sample consisting of 5.5 mol % Ta...

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1 You have a sample consisting of 5.5 mol % Ta (at. wt. 180.948 amu) and the rest Cr (at. wt. 52.000 amu). X-ray diffraction shows this sample is BCC, and Ta has substituted on Cr sites. Calculate the density of the sample in g/cm^3 if the lattice parameter is 0.29081 nm. What is the density of the sample in g/cm^3? BCC, so n=2
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2 The phase diagram shown has three intermediate compounds. The compound with the highest amount of Sl is IC1. The compound with the next highest amount of Sl is IC2, and the compound with the lowest amount of Sl is IC3. Match the question with the phase field or point on the phase diagram. Phase field showing a single phase liquid T The phase field showing the high T allotrope of IC3 plus IC1. M The phase field showing the low T phase of IC3 and Sl(ss). B The phase field showing the low T phase of IC3 and IC1. O I DON”T KNOW IF THESE ARE CORRECT B/C NO FIGURE… A.u B.17 C.q D.20 E.8 F.9 G.o H.2 I.7 J.12 K.16 L.s M.1 3 N.4 O.11 P.t
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3 Calculate linear density of a 100 direction in an elemental FCC crystal if the atomic radius is 0.175 nm. 5.71 atoms/nm 2.47 atoms/nm 2.02 atoms/nm none of the above (LD =Number_of_atoms_direction_vector_passes_through / length_of_direction_vector) Vector: X=1 Y=0 Z=0 Passes through 2 half atoms, or one total atom, and the radius length of the vector is that of 2 radii, therefore LD 100 =1/ (2*0.175nm)or LD 100 =2.857nm
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4 Crystallographic directions are denoted by: parentheses ( ) brackets [ ] braces none of the above
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5 The atomic packing factor of the body centered cubic crystal is: 52% 68% 74% (APF for FCC) none of the above
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6 Calculate the lattice parameter of a face centered cubic material with an atomic radius of 0.433 nm. 1.000 nm 1.225 nm (a=2*R*sqrt(2) ) 0.866 nm none of the above
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7 In an electrochemical cell, the negative electrode is known as: the cathode the anode the electrochemical electrode none of the above
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8 Failure where the specimen shows considerable necking is known as: brittle failure polymorphic failure cone failure none of the above
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Calculate the diffusion coefficient of C in Fe at 1200 K given the activation energy is 80 kJ/mol and D0 is 6.2E-7 m^2/s. 6.15E-7 m^2/s
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This note was uploaded on 04/15/2008 for the course CME 210 taught by Professor Kennedy during the Spring '08 term at Clemson.

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finalCME - 1 You have a sample consisting of 5.5 mol % Ta...

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