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Assignment No 2 - Charles Baxley

# Assignment No 2 - Charles Baxley - SUR 3520 Measurement...

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SUR 3520: Measurement Science Spring 2008 – Section 4218 Assignment No. 2 Student UFID: 1667-6117 Student Name: Charles K. Baxley N.B. Use tables in appendix D for the standard normal distribution calculations. 2.1 Determine the probability of having an error between -1.5 σ and +1.5 σ in a normal data set. What is it for ±2.5 σ ? For ±1.5 σ (0.93319 x 2) - 1 = 0.86638 = 86.6% For ±2.5 σ (0.99379 x 2) - 1 = 0.98758 = 98.8% 2.2 Determine the percentage point ( t value ) for E 80; explain its meaning. 0.80 = 2N z (t) – 1 1.80 = 2N z (t) 0.90 = N z (t) N z (1.28) = 0.89973 and N z (1.29) = 0.90147 t / (1.29 – 1.28) = (0.90 – 0.89973) / (0.90147 – 0.89973) t / (0.01) = 0.15517 t = 0.0015517 E 80 = 1.28 + 0.0015517 = 1.282 2.3 If the mean of a population is 2.456 and its variance is 2.042, answer the following: a. What is the peak value for the normal distribution curve? Peak Value = 1/[sqrt(2.042) x sqrt(2π)] = 0.2792 b. What are the points of inflection? ` x = ±σ = ±1.429 2.456 ± 1.429 = 1.027 and 3.885 c. Plot the normal curve showing the peak value and the points of inflection. Graph of curve is on next page. University of Florida Geomatics – SFRC π σ 2 1 ) 0 ( = = x f 2 2 2 2 1 ) ( σ π σ x e x f y - = =

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SUR 3520: Measurement Science Spring 2008 – Section 4218 2.4 The following data represent 60 observations of a random data set: University of Florida Geomatics – SFRC
SUR 3520: Measurement Science Spring 2008 – Section 4218 1.67 7 1.67 6 1.65 7 1.66 7 1.67 3 1.67 1 1.67 3 1.67 0 1.67 5 1.66 4 1.66 4 1.66 8 1.66 4 1.65

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Assignment No 2 - Charles Baxley - SUR 3520 Measurement...

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