SxN A-M Evens

SxN A-M Evens - FUNDAMENTALS Chapter 0 Sections A-K (a) d =...

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1 FUNDAMENTALS Chapter 0 Sections A-K A.24 (a) 3 23 53 1 0 4 3 21 3 2.0 10 g 1 pm (1.5 10 pm) 1 10 cm 1.4 10 g cm π −− = ⎛⎞ × = ⎜⎟ ×× ⎝⎠ m d V (b) From A.14a, density of a carbon nucleus is 21 3 1.4 10 g cm ×⋅ () 3 4 3 3 4 3 11 1 1 3 3 4 3 3 3 3 3 33 3 3 3 21 3 3 4 3 4 (5.5 g cm )(6.4 10 km) 1 m 0 k m 1.4 10 g cm 1.0 m == = = = ⋅× = × = mm d V r m rm d V d r d dr r d d A.30 Since R = R E +h , 1 = 1 =∆ = + =− ++ EE pP Gm m Gm m Rh R Gm m Gm m hh RR
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2 2 2 1 If = ,then 1 from the expansion in . 1 Then =1 1 = where =− + ⎛⎞ −− = ⎜⎟ ⎝⎠ = EE E p E E E hh x x h RR R Gm m Gm mh h Em g h R Gm g R B.8 C.8 (a) Sulfur is a Group 16 nonmetal and will form 2 anions, S 2 . (b) Lithium is a Group 1 metal and will form 1+ cations, Li + . (c) Phosphorus is a Group 15 nonmetal and will form 3 anions, P 3 . (d) Oxygen is a Group 16 nonmetal and will form 2 anions, O 2 . C.12 (a) 24 Na ; + (b) 27 3 Al ; + (c) 79 2 Se ; (d) 52 2 Cr + C.16 (a) Element E belongs to Group 16 (VI, VIA). (b) Selenium, Se. C.18 (a) 1 + 1 + 8 = 10 protons and an equal number of electrons; 0 + 0 + 8 = 8 neutrons (b) 27 26 27 26 31 30 10(1.67262 10 kg) 1.67262 10 kg protons 8(1.67439 10 kg) 1.33994 10 kg neutrons 10(9.10939 10 kg) 9.10939 10 kg electrons ×= × × ×=× Element Symbol Protons Neutrons Electrons Mass number rhenium 186 Re 75 111 75 186 Lead 208 Pb 82 126 82 208 Platinum 195 Pt 78 117 78 195 Nickel 58 Ni 28 30 28 58
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3 (c) 26 26 26 20 1.33994 10 kg 1.33994 10 kg + 1.67262 10 kg + 9.10939 10 kg 0.444649 −−− × ××× = So about 44% of my body mass is due to neutrons. D.6 (a) 24 NO; (b) 2 HS ; (c) 27 Cl O ; (d) 3 NI ; (e) 2 SO ; (f) HF; (g) 26 IC l D.8 (a) silicon dioxide; (b) silicon carbide; (c) dinitrogen oxide or nitrous oxide; (d) phosphorus(V) oxide; (e) carbon disulfide; (f) sulfur dioxide; (g) ammonia D.10 (a) 4 HClO ; (b) HClO; (c) HIO; (d) HF; (e) 33 HPO; (f) 4 HIO D.12 (a) SrBr 2 ; (b) Al 2 (SO 4 ) 3 ; (c) Li 2 O; (d) (NH 4 ) 2 S (e) Mg 3 P 2 D.24 Oxygen is present as a molecular anion in each case. (a) potassium superoxide, ionic, + 2 K, O; (b) sodium peroxide, ionic, + 2 2 2 Na , O ; (c) cesium ozonide, ionic, + 3 Cs , O E.2 The seconds in 90 years: 90 y x ( y d 1 365 ) x ( d h 1 24 ) x ( h s 1 3600 ) = 2.83824 x 10 9 seconds $ spent = 2.83824 x 10 9 seconds x ( s 1 10 $ 9 ) = 2.83824 x 10 18 dollars $ remaining = 6.02214 x 10 23 - 2.83824 x 10 18 = 6.02211 x 10 23 dollars Nearly 100% would remain
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4 E.4 Be atoms have approximately one-third the mass of Al atoms, so 21 Be atoms are required to balance 7 Al atoms. E.6 (a) moles of sand () 23 1 12 14 1000 tons 6.022 10 grains mol 1 mol 10 grains 6 10 tons ⎛⎞ ⎜⎟ ⎝⎠ (b) 23 1 31 6 62 volume of 1 mol of sand depth of sand area of United States 6.02 10 grain mol 1 m = (1 mm grain ) 1 mol 1000 mm 11 0mm 3.6 10 mi 0.6214 mi 65 m = ×⋅ × × = E.10 1 molar mass of sulfur 95.0 0.8 (31.97 g mol ) (32.97 g mol ) 100 100 4.2 (33.97 g mol ) 100 32.06 g mol 30 g mol to 1 SF −− =⋅ + +⋅ E.12 molar mass of krypton 0.3 2.3 (77.92 g mol ) (79.91 g mol ) 100 100 11.6 11.5 (81.91 g mol ) (82.92 g mol ) 100 100 56.9 17.4 (83.91 g mol )
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This homework help was uploaded on 04/18/2008 for the course CHEM 6A taught by Professor Pomeroy during the Winter '08 term at UCSD.

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SxN A-M Evens - FUNDAMENTALS Chapter 0 Sections A-K (a) d =...

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