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Unformatted text preview: padilla (tp5647) – Homework 9 – Sutcliffe – (53770) 1 This printout should have 25 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A gas has a volume of 2.0 L at a pressure of 3.00 atm. What pressure is needed to change the volume to 6.00 L at constant temperature? 1. 2.0 atm 2. 1.0 atm correct 3. 9.0 atm 4. 4.0 atm Explanation: V 1 = 2.00 L P 1 = 3 atm V 2 = 6.00 L Boyle’s law, P 1 V 1 = P 2 V 2 , relates the vol ume and pressure of a sample of gas. P 2 = P 1 V 1 V 2 = (3.00 atm) (2.00 L) 6.00 L = 1.0 atm 002 10.0 points At constant temperature if the volume of a gas sample is tripled the pressure will 1. be cut in half. 2. remain the same. 3. be tripled. 4. be one third the original. correct 5. be increased by a factor of 6. Explanation: 3 V 1 = V 2 Boyle’s Law relates the volume and pressure of a sample of gas: P 1 V 1 = P 2 V 2 P 1 V 1 = P 2 (3 V 1 ) P 1 = 3 P 2 P 2 = 1 3 P 1 003 10.0 points A certain quantity of a gas occupies 61.3 mL at 68 ◦ C. If the pressure remains constant, what would be the volume of the gas at 128 ◦ C? 1. 72 mL correct 2. 92 mL 3. 32 mL 4. 52 mL Explanation: V 1 = 61 . 3 mL T 1 = 68 ◦ C = 341 K T 2 = 128 ◦ C = 401 K Charles’s law V 1 T 1 = V 2 T 2 relates the volume and absolute (Kelvin) temperature of a sam ple of gas: V 2 = V 1 T 2 T 1 = (61 . 3mL) (401 K) 341 K = 72 L 004 10.0 points If a sample of gas is heated from 100 ◦ C to 300 ◦ C at constant pressure, the volume will ? by a factor of ? . 1. increase; about three 2. increase; about 1.5 correct 3. decrease; about 1.5 4. No other answer is correct, because the volume cannot change when the pressure is constant. 5. decrease; about three Explanation: T 1 = 100 ◦ C + 273 = 373 K padilla (tp5647) – Homework 9 – Sutcliffe – (53770) 2 T 2 = 300 ◦ C + 273 = 573 K The temperature increases by a factor of 573 373 = 1 . 5. According to Charles’ Law, the volume of the gas would increase by the same factor. 005 10.0 points A sample of a gas occupies 460 mL at 70.0 ◦ C and 1.00 atmosphere. At what temperature would the gas occupy 650 mL at the same pressure? 1. 30.0 ◦ C 2. 435 ◦ C 3. 99 ◦ C 4. 212 ◦ C correct 5. 154 ◦ C 6. 188 ◦ C 7. 111 ◦ C Explanation: V 1 = 460 mL V 2 = 650 mL T 1 = 70.0 ◦ C + 273 = 343 K Charles’s law relates the volume and ab solute (Kelvin) temperature of a sample of gas: V 1 T 1 = V 2 T 2 T 2 = V 2 T 1 V 1 = (650 mL) (343 K) 460 mL = 485 K ◦ C = 485 K 273 = 212 ◦ C 006 10.0 points The normal respiratory rate for a human be ing is 15.0 breaths per minute. The average volume of air for each breath is 505 cm 3 at 20 ◦ C and 9 . 95 × 10 4 Pa. What is the volume of air at STP that an individual breathes in one day? Give your answers in cubic meters....
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This note was uploaded on 02/03/2009 for the course CH 301 taught by Professor Sutcliffe during the Spring '08 term at University of TexasTyler.
 Spring '08
 SUTCLIFFE

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