Sample Final - Solutions

Sample Final - Solutions - _—.M”~MM 5:057“ K6115...

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Unformatted text preview: _____—_.M”~MM 5:057“ K6115? Pmflce PM i052 (o) (a) T) (5)13, (c) T, (A) F, (g) 1:, GHQ (3)7". w, m (00, (2m), (2) (A), C4) cc), (5) (e), (6") (a), (at) (c), [8) Ce), (4) (a), Cw) (a), T116Y’i were 4141? “home 035 "H42 above” ("n.o.'t.a.”>an$welr£. In (5), 'Hze, +4ij'fih7i‘ «6cm (:0 7:2(x_1)9 In (8), "HR pvofat (ed: x22) 75 460. 711.3 a; war/Q4 0141’ as «Foflews. W~< W MPCX)= P’(x):: meg-29“ Thus, P(><)=4oa?c—X7'+C, R f; given #Lml- PM): —36, {gt-RR ‘jvk Wadi/seed avg/‘wavg, ym4&%\‘h€jafivc” PTbycH’) mamdy ’36.) TACVG‘FOVey ‘36:?(0)=C/ W $9 POO: tamc~>c7l36. 336% Hows W W2): 2190—4—36, 2 'IéO, W) (“9 WM lat—:2 WM “6%”ch 0 M moo. mew”? . 3n ’ .’ fl - ‘ n “.1 .W 31772;) $33 0.5;) "afifmwém I ‘ J- -4 _ ‘1 jg; [WW] = 4 09) PCPO eat; given 26% 2 P mM$/ ’k: 3 NOW E :: FYe‘seM-j‘» \falbte cashew? M 540/000 {cm 40 74643). The“ 40/6002’3761011‘ P 40. 0&0 __ 44,...— F 170 000 [0000 8” 609%. (ebzf/Lf“ 13/4. (42) (a) Sfix—rfiotx: Q2+x"7—+L)&x:2§~é +zx+C1 "PC g M e‘4t C107 fm'l'e )At» CANON) + (4) + C 2 4..“ _ H “lb-561 4* +C‘ ‘ [Regan M fCa2K=é*-b)“dx : $819+: 43502 “5': ‘1' 6'2) (C) 5% “9‘16” xMX: EXZMV. x,- i {In jawed) [£CX)AX: 7609] bvl M 53-31 ’H/LL defivwW Mack?! a7 Majfirn v WM” 7”“ W “1&0 “WC ‘59 fig’fxwxr—gwfl’. (4) W4“ ' an) “5, w)?» m jziii =Z:('wea of <9 out ma. 4)+ [g L, l2x+1| j: 2% a, , 2 03) C“) : (‘7’: 'it(—2)C—1):2. wkM— 93 it? ( V fl“ 1"“ bi+1>+ ’eh +£V} (Xl+2x—1)/ 0/ 2') ..—L 4.1 ~— 1 8% I “#73 we, W 3 dx ~ X4j+1 + 2&3 + XL+2xAl VL a; . a) w? 0 Z; ’L‘ '2 «1—. .3 fli... 2:“. We (3% 24/ wmwwxamm (01 x V A amen: ’ ) 29-22 40cm». M ‘02 it: ~ ~ 31902,! W Pita-2: SCé)-5(0)=_Q£C2t+4)d’c = 1&ch: 2% +5 :#2~ft. (44) (a) 71m x— Mlcvozp‘b ML x=i M x43 J 5'0 441% [email protected])(w—3)dx 1f13€xl+9X~3)ch = A EEHXLHN]: ;%-9+/g—?-(§L+2~3)=~3‘4+i=—;t‘ I (b) 5% figure. 'toiik‘ejlf'ifiéfitig To damn/Mm ,M W Cum/e5 we. solve x’firxczq, 0r 0: x°’+zx~3=(x+3)(><—1)I" I} getting" ><=11. “MA X=~3 as r0043. The desired 560m. QMZI1E3AX~(XEt—x)]cl7( _ > ‘1 (3" ZX—X/acflx 2 “3x5:ng 1.13:1. éuf_9_q+q] 23:23“. :1 cf- w.“ x » oh‘fi’qu yoth Mia : 0&3)" (>93? ‘— (Dc—3)”— J 90 [406) mm OvCVL‘FCaLQ pom/973; 2520/ WM? 1:6, 15%»; "mag MW: _ rfljuiY-Qd kimio 3;— +§l7~~=i) 07'. LPX+37=ZVE 7147 man/away #t‘amJ/b W W té'é‘g zfly. (~16) Firsb Whey-1L e">‘>0 *vv «111 x) 50 “fire/*6 L5 & X“"‘Jf€"‘€ft Meme y—thfircep’f '5 {(0)=’I+1:2. 7716” are flasymffiué W Lim 7C(x>:oo. NWWOQ: exveh)‘ :- e £1 X9100 5%”? ‘7‘“ WM” ’65 02 WSW ear—1 90 1:0 4' 4m 77111.5, x20 ‘1’!”de m 910104 Mwimum {(0)22} Wfixere 1‘s _@ flfixobafl mx7mum, , Find?» 4 "[X): 69% e‘)‘ 2 H2) >0 Fifi—WW M2 07a7qx> 1‘5 CU awrwa) MAM M [mt/(2 ah‘oh. “yo/wits» We gran/9% 1‘s Symmefiw wmi‘. “Hoe y~axfs s‘z‘mce 1C(~X):—F(?c) 4w (LU ...
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This note was uploaded on 02/03/2009 for the course MATH 16A taught by Professor Stankova during the Fall '07 term at Berkeley.

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Sample Final - Solutions - _—.M”~MM 5:057“ K6115...

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