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# solution_pdf - muir(cem2577 H01 concentrations McCord(52405...

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1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points How much NaNO 3 is needed to prepare 225 mL oF a 1.55 M solution oF NaNO 3 ? 1. 12.3 g 2. 29.6 g correct 3. 0.244 g 4. 0.132 g 5. 4.10 g Explanation: V = 225 mL M = 1 . 55 M ? g NaNO 3 = 225 mL × 1 L soln 1000 mL × 1 . 55 mol NaNO 3 1 L soln × 85 g NaNO 3 1 mol NaNO 3 = 29 . 6 g NaNO 3 002 10.0 points What is the fnal concentration oF NaOH when 335 mL oF 0.75 M NaOH are mixed with 165 mL oF 0.15 M NaOH? 1. 0.55 M correct 2. 0.82 M 3. 1.67 M 4. 0.45 M 5. 0.18 M Explanation: V 1 = 335 mL M 1 = 0.75 M V 2 = 165 mL M 2 = 0.15 M Molarity is moles solute per liter oF solution. Two solutions are being mixed together in this problem. We fnd the moles oF NaOH in each oF the individual solutions: ? mol NaOH = 335 mL soln × 1 L soln 1000 mL soln × 0 . 75 mol NaOH 1 L soln = 0 . 2512 mol NaOH ? mol NaOH = 165 mL soln × 1 L soln 1000 mL soln × 0 . 15 mol NaOH 1 L soln = 0 . 0248 mol NaOH The total moles oF NaOH in the new solu- tion will be the sum oF the moles in the two individual solutions: ? mol NaOH = 0 . 2512 mol + 0 . 0248 mol = 0 . 276 mol NaOH The total volume oF the new solution will be the combined volume oF the individual solu- tions: ? mL new soln = 335 mL + 165 mL = 500 mL soln To calculate the molarity oF NaOH in the new solution, we divide the total moles oF NaOH in the new solution by the total volume oF the new solution: ? M NaOH = 0 . 276 mol NaOH 500 mL soln × 1000 mL soln 1 L soln = 0 . 552 M NaOH 003 10.0 points What is the molarity oF a solution containing 3.50 grams oF NaCl in 500 mL oF solution? 1.

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solution_pdf - muir(cem2577 H01 concentrations McCord(52405...

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