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Unformatted text preview: 10. 1 u has anode halfway between the two nuclei in a diatomic molecule. 1 u has a node along the internuclear axis but no nodes between the nuclei. Therefore, 1 u is antibonding, while 1 u is bonding. 1 u is lower in energy because it is created from s orbitals, which are lower in energy than the p orbitals that combine to form 1 u . 11. 1a 1 2a 1 1t 2 2t 2 3t 2 1e+1t 1 a 1 +e+t 1 + 2t 2 t 2 a 1 P PO 43 4O O P O O O3 AB 4 , tetrahedral pt. grp. = T d T d E 8C 3 3C 2 6S 4 6 ! d unshifted 4 1 2 contrib. 31 " red 12 2 N A1 = 1/24 [12 + 12] = 1A 1 N A2 = 1/24 [12  12] = 0 N E = 1/24 [24  0] = 1E N T1 = 1/24 [36 12] = 1T 1 N T2 = 1/24 [36 + 12] = 2T 2 " red = A 1 +E+T 1 +2T 2...
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This homework help was uploaded on 04/18/2008 for the course CHEM 131 taught by Professor Landry during the Spring '08 term at Vermont.
 Spring '08
 Landry
 Electron

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