test2practicesolutions

test2practicesolutions - 10. 1 u has anode halfway between...

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CHEMISTRY 131 Spring 2006 Answers to practice problems for Test #2 1. The central atom does not have 8 electrons in the picture. The best structure will give every atom an octet, will have minimum formal charges on each atom, and will include resonance if it exists: O O O 2. N 2 O: 2N O 10 6 16 4 12 1 2 N N O 0 +1 -1 NO 2 - : N 2O chg 5 12 1 18 4 14 1 2 2 2 N N O - - most likely because it places negative formal charge on the more electronegative atom - includes resonance and places formal charge on more electronegative atom 3. O O O AB 2 e, bent N N O AB 2 , linear N O O AB 2 e, bent - 4. F Se F O F - F Xe F F + AB 4 e, see-saw AB 3 e 2 , T-shaped O Te O O O -2 AB 4 , tetrahedral Cl I Cl Cl Cl Cl Cl + AB 6 , octahedral 5. Point groups, in order: D 2h , D h , C 2v , C 2h , C 2v , C v . 6. D 6h , C 2v , C 2v , D 2h , D 3h , C 2v , C 2v , C 2v , C s , C 2v . 7. C 1 , C 2v , T d , O h . 8. 1 σ g is formed from s orbitals, while 2 σ g is formed from p orbitals. 1 ! g : 2 ! g : 9. “g” = gerade; the sign of the molecular orbital wavefunction remains the same upon crossing through the center of the orbital; “u” = ungerade; the sign changes upon crossing through the center of the orbital.
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Unformatted text preview: 10. 1 u has anode halfway between the two nuclei in a diatomic molecule. 1 u has a node along the internuclear axis but no nodes between the nuclei. Therefore, 1 u is antibonding, while 1 u is bonding. 1 u is lower in energy because it is created from s orbitals, which are lower in energy than the p orbitals that combine to form 1 u . 11. 1a 1 2a 1 1t 2 2t 2 3t 2 1e+1t 1 a 1 +e+t 1 + 2t 2 t 2 a 1 P PO 4-3 4O O P O O O-3 AB 4 , tetrahedral pt. grp. = T d T d E 8C 3 3C 2 6S 4 6 ! d unshifted 4 1 2 contrib. 3----1 " red 12 2 N A1 = 1/24 [12 + 12] = 1A 1 N A2 = 1/24 [12 - 12] = 0 N E = 1/24 [24 - 0] = 1E N T1 = 1/24 [36 -12] = 1T 1 N T2 = 1/24 [36 + 12] = 2T 2 " red = A 1 +E+T 1 +2T 2...
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This homework help was uploaded on 04/18/2008 for the course CHEM 131 taught by Professor Landry during the Spring '08 term at Vermont.

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test2practicesolutions - 10. 1 u has anode halfway between...

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