Intro physics exam answers 4 - PHYS litil — Final Exam....

Info iconThis preview shows pages 1–15. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
Background image of page 13

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 14
Background image of page 15
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: PHYS litil — Final Exam. "£002 NAME: i493 . cat-«TEE: STUDENT NUMBER: OKANAGAN UNIVERSITY COLLEGE PHYSICS DEPARTMENT PHYSICS 122 F INAL EXAB‘IINATION Wednesday, 11' April, 2002 TIME: 9:00 am. - 12:00 p.m. Instrucmrs: Chris Melin. D. O'Brien, T. Wrzesniewsl-ti mm: - Calculators and a two+sideri formula sheet can be used. Computers and QWERTY board calculators are not permitted. Answer the examination questions in the space provided, or clearly indicate the location of your solution. You can use the backs of pages for calculations if necessary. You must clearly show your method to receive fiill credit. if you cannot solve a port of a question and the resiilt of that question is needed to do the remainder of that question, you mag.r invent an answer for that question part, and clearly State that the answer is invented, and proceed, with the remainder of that question. The pages in this examination are numbered from 1 to 15, including this title page. This examination is our of [$0 points. ’- Note to jgvigilator: This examination does not require examination booklets. QM: k e seems” smite: e, = assets“ citith qimn = 1.602(10'19 C nu=4rtxllTTTran g=9.31m’sec= mesmfi 9.11::10‘“ ks Po= LIIr'litllll1 Pa “Imam: 1_6?x10v21kg I" J’ c. e. b D T T C c 'T' i" thiflnl‘ Elia” #9 #1" all files possible a -. l n 1 Grade obtained PHYS [22 - Final Exam, 2002 Marks Part I: Multiple choice questions Circle the correct answer for each queSIion. There is only one correct answer in each case, A blank answer is a wrong answer. 1 1. If the distance between two point charges is tripled. the mutual Electric fDrCB bBtWCEfl the two point charges will be changed by what factor".I a. 9.0 b. 3.0 c. 0.33 @to I E. An electron enters an electric field with a velocity 1.- . With respect to the field, the electron experiences a force acting: a. parallel to the electric field and pointing in the same direction as the electric field @lparallel to the electric field and pointing in the direction opposite to the electric field c. perpendicular to the electric field. cl. always in the direction of electron's velocity. 1 3. Consider the electric field between the two parallel plates of a charged capacitor. Which of the following statements is correct? a. the electric field is strongest near the posnwe plate b. the electric field is strongest near the negative plate c. the electric field is strongest midi-tray.r between the two plate: @the electric field is constant throughout all of the space between the two plates 4. The direction of the magnetic force on a current: carrying wire located in an external magnetic field is: h—t a. perpendicular to the current b2 perpendicular to the field EDD-filth answers [a] and (b) are correct . neither (a) nor (b) are correct 1 5. The path of a charged particle moving parallel to a uniform magnetic field will be: g} Straight line . a circle c. an ellipse d. a parabola It.) PHYS 122 - Final Ham. 2001 Part1]: Solve the following Emblems #1. The point charges Q1 = 2.00 ttC, Q; = 6.0-0 tit: and Q; = 4.00 ac are located as shown in the accom- panying diagram. 4 a} Calculate both the magnitude and direction of the electric field at the origin due to the three point charges. El: (F1 :0) = {H.5'al03l D J “III: ‘2 k: i 5 [0: Fa‘) : ( D I 13.53;“.95) U/C PE? 3 h] A point charge Q4 = -S.{}D tilt: is placed at the origin. Calculate both the Enamel; and direction of the electric force on the point charge (2.; due to the original three point charges. _. .— 5 _, Fur g I? : {— 5.00:: I0 6,43,] sigh/1'0 y; a} ’22:.) o .. / Wrath j l-J e} The point charge (1.. = 6.00 w: is removed to an infinite distance from the origin. Calculate the absolute electric potential at the origin due to the three original point charges Q1, Q: and Q3. kfll Rat; I-CQ3_ It“. Vo=u,+uy”3" 3r“ 1' '1'" new a) PHYS 121 - Final Exam. 200?. 2 d] A point change Q5 = -]fl.fl LLC of mass. 2.0mm“ kg is releascd at rest at the Origin. Calculatc the speed of the: paint charge Q; at an infinite distance from the origin. ¢?Eu +¢KE :0. t flgfvr—Uo) + "iffl—O) = 5' .fi'w‘f'o—IH..QJE__ (10.ovmorfi){3Y-‘?6“03) ; {U}: 6:0ng “143'. 2 e} The point charge Q; is remand to an infinite distance from the origin. Where should a point charge Q5 = EDI} M; h: placed on the positive x-axis such that the absolutc electric potential at the origin is zero. PHYS 112 - Final Exam,2002 In.) #2. There is a unifom electric field between the plates of a charged parallel plate capacitor as shown in the autumn partying diagram. The distance hetwe en the plates of the capacitor is 5.00 mm. a point charge Q = 2.03 cc of mass moxie” kg has initial upward velocity vi, = acetic mfsec very' close to the lower capacitor plate. The acceleration of the point charge Q pcintc dcwnward and has magnitude -" 1.0flx1flm mate. a) Does the electric field point upwards or do we b) Calculate the magnitude of the electric field. E E 159' a " m. E = '3’ J I, -u“ 0 a2.»— _ Lona (LI-9W .5.- M f‘mplo'q c] Calculate the electric potential difference between the capacttcr p a es. E: cg I flu? Ffl'fl? [01:03:11 ¥(19-905)““2-$in0 V d) Which capacitor plate, the upper plate or the [exact plate, is at the higher electric potential? " UPPEV’ :2) Calculate the maximum vertical height above the lcwet plate that the point charge Q needs before itccmcs m reSL w t: giwrcafi : 2 y LEO H9"? I0: ‘3 “3"” m, memo m Jeane ‘3 PHYS 1‘12 — Final Exam, 2002 1 r0 #3. Four resistors, R; = 5.00 (1. R: = 30-0 511 R3 = 20.!) fl and R4 (the valor: of which is unknown} are connected to a orator}.r of voltage 155.0 V as shown in tho accompanying diagram. 3 a} The equivalent resistance of the four resistors is 13.0 1.1 Find the value of rho unknown rcsistor R4. Hora—ER=E_‘3:. J. _ .L- J sti- g 3 8’0 29 *9 fl-L~%=ir so *9 '9 5v Rq’ "£2" ’64::- :- fl 2 b) The voltage across the resistor R. is 15.0 V. What is the current passing through tho resistor R1? V ZI. DU I" 'E ' -~ [534 5‘3 2 c} Find the current passing through the resistor R1. 1‘52: 55V-25U:WV =' “’5 '5 Vi! ' -U _, W” s 60.5% Its—£23" 3’93 2 d} What is the power lost {dissipatodj in the resistor R3? U3 you : —— "- I-—— n- ?3... 1392;: (2.0)?, 29.12 _. Wm; } PHYS 121 - Final Exam. ENE 2 e) 1What is the total power provided by the battery? .4 .— SV>LSA= Far-"F— J-_F_— I I 2 D What is the tetai power lust in ail of the resistors? 5 #4. Consider the e1e¢lric circuit presented item. Find the currents I! and I; and the unknown electromntive force 2. Use the Currents with their assigned directions as shown in the diagram. in) il+i2 =2. (a —15'+(2r§)+-}'fl=0 C3) g-2_ra—io=o —$+¥ff-0 5-2(2—1“) —t0=' 0 ~5+¥Ir=0 E+2f}-19=0 f2 = 2 — eat-mi = 1.29614. 8 = IO + .251 = i0 + attzé’c): 12.51v i = . A i 1: 1196 f“ i - haflv j _,_ ,;._rJ¥-= PHYS 12?. «- Final Exam. 211}? #5. A resistor R = 100 o and acapacitor C = Lt'ioslttr1 F are connected to a 100 V hatter}:r as shown in the diagram. The switch 5 is initially open and the capacitor is initiain unchargedr R gm At time t = 0.00 see. switch 5 is closed. Imv 2 a} What is the current passing through the resistor R after switch C 5 has been closed for a very long time? 0/51 2 b] What is the charge on the capacitor after switch 5 has been closed for a very long time? ' Vfieioou G=urg =|aovvaotr .- [.000 L. 2 c] In the coordinate system provided 1:10! the charge on the capacitor versus time after the switch 5 is closed. 2 d.) .Calcuiate the voltage across the capacitor after switch 5 has been cioscd for LDD sec. " it. "" v“).- ummw ) t.ac=t.oo_<, Vfl) = i00u( 1-94) WI] .~ 'ODufi-EP»368)= 631v PHYS 112 — Final Exam, 101i}? After a very long time. switch 5 is opened. And next a dielectric of dielectric constant 1: = 4 is, inserted into and c-zttnpletclj,r fills the capacitor. 2 fl What is. the voltage across the capacitor after the dielectric has been inserted? cl: "It. to .— can no"; 1“ GI I: a! D a . Lam? F: 251/ VI = “a.” mounts“? #6. Two infinitely long wires. carry electric currents I. and [3 both of magnitude 4.00 A into the paper as shown in the accompanying diagram. A third wire of length 5.00 m carries a current [3 = 6.00 A out of the paper. 2 a) Calculate the magnitude of ihe magnetic field due to 11 at the location of wire [3. e 2 4 _. i3: $3" “"0 ' unto? tr. My 2 b) What is. the direction (Le. angle} of the magnetic field due to the current IL at the location of wire 13.“? l- 309 K - is: IT 3 c} Calculate the magnitude of the net magnetic field at the location of wire [3 due to the currents I; and I2. 45 “'3 z B '3 Hr: It ; 131] I1] BM: ‘5‘: £321"? Fit-$339, ET = 0 ii! is 1' 15 i. 3L PHYS [22 — Final Exam, 201)”: 3 d) Calculate both the magnitggig and directifin of the net magnetic force due to It and I; on the currentig. _-,-: ___ tar Law) lg“; hr _ J - t M. 1 any}: (3.25m r 6.90.4) g (SQOM), 1.09::me id, c (of Laura‘ru) #7. A singly charged positive ion has mass rn = 3.201(10‘26 kg and velocity 'u" = 4.ti[inl{l5 W5. It enters a uniform magnetic field B = 3&0 T which is perpendicular to its velocity and directed into the page as indicated in the accompanying diagram. 2 :1} Indicate in the diagram the direction of the magnetic force acting on the ion when it enters the magnetic field and sketch its trajectory. Ix.) h) Calculate the radius of the path of the ion in the magnetic field. ll] PHYS 122— Final Exam, 1002 #3. Consider the accompanying diagram. A conducting he: of a. length i = [.5 m slides at constant speed v without friction on the corn dueting rails connected to the resismnce R = it) It. The resistance of the sliding rod and the reiis is negligible. A uniform magnetic field B = 2.5 T is directed into the page; t a} What is the direction of the induced current I in I the resistor 3'? Circle the correct answer of the two following statements: '1' he induced current I is directed upward in the Esistor R. The induced current [is directed downward in the resi tor R. 7 h} At what speed it should the conducting her move to produce an induced current of I = 0.50 A? grad-“Dr 31.2 = IR_ (new) 50m _ gm 1; iii—t." 0-6 ’5 2 c) What external force is required to move, the her with the constant speed It culminated in part b above? ?e : q’eti: W Feet: BIL IN? = Par : (rsrflosanflisc) = ‘f = 1.9155.) PHYS In — Final Eaa mi 2002 #9. A cylinder of Sfllid uranium weighs 9 [.5 N in air. When attached to a spring scale and completely immersed in water (see the accompanying diagram], the cylinder weighs 36.6 N. The density of water = LEI]: [El] kgfmj. 2 a) Draw ti free body diagram of the cylinder of uranium. Show all the forces acting on the cylinder. '5 2 1:) Calculate the volume cf the. cylinder? T+FB.—u F=”'T' H” FB= gea‘unqt ? _t. 5 F3 _ emu ‘ 501103" "e! - may Walter M W 1 c) What is the density.r of the cylinder? '4 k {.5 A! _ Ho 31% .. —.l'd—_—-.:' 9 'ir 3 I a 3' 2 d} The cylinder of uranium is next completely immersed in ancthet liquid and the scale reading is now 24.9 N. What is the density cfthis liquid? = etc-2H .- (6.610 = git-lg; «3. w #1 «£01 .. MW: ifiéxlfll' l! 5 S" H (5,0;ro"fiu.‘){wh/s') 3/” l2. PHYS 12?. - Final Exam RUDE #10. Water is flnwing Hu'nfig through a cylindric 31 pipe 1’1. of varying cross section and elevation as shown in the accompanying diagram. The lower section ef the pipe at {he left of the die; mam has :1 cross section e * “A; = 1.50 em2 anda speed Sat-"nil 2'50”) of water through this seclien V] = 6.00 1111's. The narrew P1, upper section of the pipe h a crass section A: = 15¢} em2 1,. 1: O and the speed of water through the narrow section is #2. The difference in elevation between the two sections of the pipe is y = 153 m. :1} Calculate the speed Va. A. 11' i = ' :4 a ‘1; 1 0a a MI: .2’SO)( an :- M/S 7 h) Calculate Lhe difference of the pressures 3p- : p; ~ [:1 between points I. and 2. [-3 P, W7": w‘flzr e «535.: eye? PR‘PJ ‘_ ijtJ'z) 4if(¢52‘%£2/) 0 192‘?! ‘= WWW“) (4.5) 4 fi'f_0ria3(§a- ml) 3 -p, .7(;.om")[-ac.;Je,=.-qc.1 km W PHYS m - Final Exam. 1001 3 #11. A small lamp is 1G m below the sulfate of a lake. It emits light in all directions. A heat goes from directly above the lamp to the point when: the lamp can no longer be seen. How far does the heat travel? The index of refraction of water. :1 = 1.33. Sketch a diagram illush-atlng your solution. , ml Sign. ’F’ e. f ,‘ifcs‘iflg‘m'lw x=ii+au9 4r “9" imug'q '1 I}; =' :-‘1 he. i #12. Considerflue diagrambelhw. Aconcave mil-mt with radius ofeurvnrurc = . cmis placed 5.00 em to the right of a converging lens of a focal length f = 2.00 cm. A 0.90 cm high object is place-:1 5.00 cm to the left of the lens. The points labeled f in Ihe diagram are the fecal points of the thin lens. The point labeled 0 in the diagram is the center of curvature of the concave mirror. 2 :1] Draw a ray trace in the diagram above to find the position of the image formed by the lens. Label it 11. PHYS I23 — Final Exam. 2cm 2 b) Using the thin lens equation calculate the position of the image formed by the thin lens. Note: your answers to parts a] and b] should be consistent. ' .L + J” 5 i:- a “h ' J, a _ J- - J7. 3— : ' ' 1 5 t a i”: (ll ; '55. 153 can 2 c} Calculate the magnification of the image produoccl by the thin lens. _ art _ H333 HI: Tap 2 :1) Draw a ray trace in the diagram above to find the position of the image formed by the mirror. it I3. ¥l=g~= Law 2 e) Calculate the position of I; with respect to the mirror. 2 Pi: 6.00 - “5.32_,.- 2.63m. L+Jc_c.t. $12!.GCM} ‘1 P1 'E z I_ - .1. — i- 1: | .2 E? 2 E) Calculate the height of the image 1;. Hint: check that your calculations and drawings are consistent. .. $2, LG H : __f_ = __,_,_ i was a 2 Pa- H-I-N : Ht “1 H1 _- {C— 0.6?)(1-0. 6) : LI 0 h'= h-“tafi 0.!30Lh * U-HG: !O."56CM4I IS ...
View Full Document

This note was uploaded on 04/18/2008 for the course PHYSICS 123 taught by Professor Wrzesneski during the Winter '08 term at The University of British Columbia.

Page1 / 15

Intro physics exam answers 4 - PHYS litil — Final Exam....

This preview shows document pages 1 - 15. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online