Physics Assignment - KEV Print full name Phys 122...

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Unformatted text preview: KEV Print full name Phys 122 Assignment 1 Due - Jan 25 Name: Show all work. Include diagrams whenever applicable. Place your solutions in the space below each problem. Place the final answer in the box provided. It makes it much easier to mark. 2 All assignment pages have to be stapled together WITH A STAPLER. “he k a, p ’40 7 WC/ 2 Include units with your final answers. “f 1. A charge q}: + 40. x 10'6 C is located at point (0.0 , 0.0) m and a charge q; = -20. x 10'6 C located at (8.0 , 0.0) m mg:££.o.90 ; 10. l 5!.“ a .1- ELE. a 0. _ (0. fig IE; I k“ =W=Zfiixoi n r ("-0)1 I6 _‘ {5/ = W): [/15403 “E’— s : / 5' . x I»; 1.51/04 % vi-‘rllEh:(3.58xlOH‘ O) a) Determine the electric field at points A (4.0 , 0.0) m and B (8.0 , 6.0) in due to the presence of the two point charges. Give you answer in components. [4 marks] 0 8 bf‘ : _ filoqylroz/o'cl x) - rJ-a "03 [501'( ’02 = 5.6xlo5 Eng-(3.60550, 3.65: a) *6 .3 _ 3 lafi)’ W EZE=( 0 I ~b.0 )K/O 66 _ 9 u r EA= (5.53M? , 0 6 E5: (2391105 ,-,229x!05)% b) Determine the potential difference between points A (4.0 , 0.0) m and B (8.0 , 6.0) m, ( VB — V A), due to the presence of two point charges [3 marks] V Jim’ovfl’o‘m—C) * (flax/oyfizo‘m“) : 45; ml: 1/ A LAO 9p .5 _6 V -_ 9.01/09)(LI0110 ) f (-Jo‘rlo : B /o 60 , é _ t, Via—VA: (06*‘1-5)xl0 l/ = 5.6ix10 l/ VA7 VP; 3.16,?th We c) How much work would be done in moving a charge Q = +5.0 x 10‘6 C from A to B? [2 marks] “1% = 62 (VBJA) .— (bfaz/o'éC)[—§4 U0 9 V) Wm : —0. H2567 z: —0.20f (1) Would this work be done by the electric field or by an external force? [1 mark] Wed 40 so mule 1's 0/0146 7%? flake/4'41 2. Two point charges, Q; = 12 n0 and -5.0 nC lie along x-axes. Q is at 0.0 m and 02 is at 1.0 m. a) Find the point, other than infinity, at which the net electric field is zero. Show the diagram. [4 marks] :iznc 7,:—50 6" a’ 0“ EZMP o I. 'M7X , X (M ) /5/:/E;/ , /t</x;1xLe/“"’__ Saw—"9 /[-7 (7X_2_.Z‘1 aw); ' X2 ’11; 3A6 _ 2.29 [+1 V 7 X=Lgtfm 740m a? 3,qg.x = 2.2HIM) 00 ?= 3-5)? 0 <5.‘ré~o‘2.2‘1)x = 2-29 ( ' )M b) Find the point (points), other than infinity, at which the net electric potential is zero. Show the diagram. [4 marks] (Pt (92 Ml 42/622 LOW @ + {=0 X19) @=0 ’4' XI @ (+11 )Cz 12; _ ,5: ,2 5. I‘X, — K, ——'--— : -'~ l$( : [Hag XZ l7x': 5' Zara : 5U+zd XI:/r—6¥: :5— X s 0‘26? yxz" y / I M XL: %: W: M (0750)” 222: {/7/,0jm 3. A negatively charged oil drop of mass 1.96 x 10‘14 kg is allowed to fall between two parallel plates connected to a variable power supply so that the potential difference between the plates can be changed. The potential difference is adjusted so that the oil drop is held stationary between the plates. a) If the potential difference between the plates is 6000 V and their separation is 4.00 cm, what is the magnitude of the electric field between the plates? [1 mark] AV éooov 5 v a [E - 7 = = rsuo " (0" c, l 0 0.0WOM M ) b) Which plate has the higher potential? Select the one of the following: [1 mark] Upper plate lg lower plate c) What is the direction of the electric field? Select the one of the following: [1 mark} E is pointing up V E is pointing down [A d) Calculate the magnitude of the electric charge on the oil drop. Draw a free body diagram. [3 marks] Fa “[3:1-5 M ~l‘r ‘8’ 5 firi= "qéf’o )(q'?) Haw/0’9 1,5uog e) Calculate how many electrons are present on the oil drop. [2 marks] J? l aéedwu 129x10 C x M m = 87 aka/vows .xlO' C 4. Consider a system of three charges: q1 = 4.00 uC is at the origin, q2 = 6.0 uC is at (0.350 , 0.000) m and qa = -4.00 uC is at (0.350 , 0.200) m ( see the diagram). —7 "E: 5: mo: ,7 33 El ' ( 0 l El ) EL: (‘ng9, 5251'“ %:(E310) a) Find the electric field, E, at pointP (0.000, 0.200) m. Give the answer in components. [3 marks; J) g V lr7l=L——7;"'0“°" A «WM 5,: (o , 9.9”” 2 l C0.Z.oo)2— S _, ~6 — I? = 4.? . M [52’ : 7.0::0‘1 {66:10 ) __ 3.5x,05% 7 { leI/IO C {0&0} _. - g = 2.4 0))(1059 ‘i . x ‘J 3 ( I 0 2?: ):(7.0110C 8M!) 10 :gqulos’gf £35”sz 4: 6 A; EP:(~0/ LHIO a) b) Find the electric potential, V, at point P. [2 marks] _ , oz 9.0 E}; (4.0 ’5 VP' Vr+V2*V5' qua (m*D.Qo5+E§JE H0 .3 - VP _, mono (.20 419.4 —//.c,) = 2.1;!105 \/ c) Find the potential electric energy of the system of three charges above. [4 marks] Note: The electric potential energy of a group of charges is equal to the work required to assemble the group of charges. - _ lc “w “w “MW - 0+11l%‘ltlaklé'fi*7f 3 l -c . _ 37E; =(r.ouv")(q'”“oq {W’mj'l'(“today/401m? ‘“"“"+ «W. ‘6’ (2m 0.100 (0. 35"0 77559,, : — 0. 827/ 5 {_ 5. A plastic pellet has a mass of 7.50 x 10 "° kg and carries a charge of 2.00 x 10‘9 C. i; 4;. The pellet is fired horizontally between a pair of oppositely charged parallel plates, as shown below. The length of the plates is 2.00 cm. If the electric field strength between the plates is 9.20 x 10‘ MC and the pellet enters the plates with an initial speed of 150 mls. determine the deflection angle. 6. Hint: this problem is similar to those involving projectile motion in gravitational field. [6 marks] fraud—‘7 I3 Meyer-Ale /- “rm/z a an»: W: " -5 . e5 T}; aj' m m '.. ‘ ‘ ‘ * - down. (9 X: v0; 19 ‘9 , 0 0200 = 150 -t =2 l = 041553;”: max/o 5 £2 @ = V0j : 0+ I '92 9) J: V :_(_.2.00uo (9.20.40 I J—_ - h j Esme/0’” “Mam - 5‘77? ~37 V} = (va V3) = (150 ram) M/s lS'O .- I‘ o -324 ’. we: 75.0., .7 0 22.3 ...
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This note was uploaded on 04/18/2008 for the course PHYSICS 123 taught by Professor Wrzesneski during the Winter '08 term at The University of British Columbia.

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Physics Assignment - KEV Print full name Phys 122...

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