HW_4_Solutions - ECE 432 Introduction to MEMS Sunil Bhave...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECE 432 Introduction to MEMS Sunil Bhave Homework 4 Solutions Fall 2007 Problem 1a By definition, moment M(x) = Force x Moment Arm = L x x M ) ( ( ) x x dx ' ' Where, dx is the force over a small length dx and (x-x) is the moment arm. ( ) ' ' ) ( dx x x x M L x = = L x xx x x M | ' ' 2 1 ) ( 2 = 2 2 2 2 1 2 1 ) ( x x Lx L x M + = 2 2 2 1 2 1 ) ( x Lx L x M [ ] 2 2 2 2 ) ( x Lx L x M + = ( ) 2 2 ) ( x L x M = Problem 1b ( ) 2 2 ) ( x L x M = 2 2 ) ( ) ( dx x y d EI x M = ( ) 2 2 2 2 ) ( x L EI dx x y d = ( ) 2 2 2 2 2 2 ) ( x Lx L EI dx x y d + = + + = a x L Lx x EI dx x dy 2 2 3 3 1 2 ) ( a dx dy = = ) ( L x + + = b x L Lx x EI x y 2 2 3 4 2 1 3 1 12 1 2 ) ( b y = = ) ( + = 2 2...
View Full Document

This homework help was uploaded on 02/22/2008 for the course ECE 4320 taught by Professor Bhave during the Fall '07 term at Cornell University (Engineering School).

Page1 / 5

HW_4_Solutions - ECE 432 Introduction to MEMS Sunil Bhave...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online