Lab3 - Kazi Sakiouzzaman BIO 356 02-23-08 Lab 3: Population...

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Kazi Sakiouzzaman BIO 356 02-23-08 Lab 3: Population Regulation 1. Use the curve in Figure 1 below to calculate R, the growth rate, and the population abundance in the next time step under the following two scenarios: N(t) = 60 and N(t) = 400. Compare the growth rates at these two different population sizes. What inferences can you draw about the biotic conditions faced by these organisms at each of these two population sizes? N(t) = 60 At the next time step, the ratio of N(t+1)/N(t) = 2.4 Thus N(t+1) = 60 x 2.4 = 144 Calculating R R = N(t+1)/N(t) R = 144/60 = 2.4 N(t) = 400 At the next time step, the ratio of N(t+1)/N(t) = 0.7 Thus N(t+1) = 400 x 0.7 = 280 R = 0.7 At the population of 60, the population may have had favorable biotic conditions necessary for reproduction. This is including but not limited to: high supply of food, favorable reproductive atmosphere, healthy offspring etc. At the population of 400, signs of population overabundance seem to have taken place, as the population ratio N(t+1)/N(t) steadily decreases. Since the ecosystem always has limited resources,
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This lab report was uploaded on 04/18/2008 for the course BIO 356 taught by Professor Ginzburg during the Fall '08 term at SUNY Stony Brook.

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Lab3 - Kazi Sakiouzzaman BIO 356 02-23-08 Lab 3: Population...

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