Crystalline Solids_crystalline and non-crystalline solids

Crystalline Solids_crystalline and non-crystalline solids -...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
Materials Science and Engineering MIME 1650 Lecture 5 1 1 Chapter 3 - MIME 1650 Materials Science and Engineering Lecture 5: Crystalline Structure and Miller Indices 2 Chapter 3 - Point coordinates for unit cell center are a /2, b /2, c /2 ½½½ Point coordinates for unit cell corner are 111 z x y a b c 000 111 Location of any point within a unit cell can be described using generalized coordinates q, r, and s q – fractional length of a along x axis r – fractional length of b along y axis s – fractional length of c along z axis Convention qrs (no spaces or punctuation) Section 3.8 Point Coordinates
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Materials Science and Engineering MIME 1650 Lecture 5 2 3 Chapter 3 - Crystallographic Directions 1. Vector repositioned (if necessary) to pass through origin. 2. Read off projections in terms of unit cell dimensions a , b , and c 3. Adjust to smallest integer values 4. Enclose in square brackets, no commas [ uvw ] ex: 1, 0, ½ => 2, 0, 1 => [201] -1, 1, 1 families of directions < uvw > z x Algorithm where overbar represents a negative index [111] => y 4 Chapter 3 - Crystallographic Directions Certain groups of directions are equivalent since they are the same as other directions if we redefine the coordinate
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 04/18/2008 for the course MIME 1650 taught by Professor Burham during the Spring '08 term at Toledo.

Page1 / 8

Crystalline Solids_crystalline and non-crystalline solids -...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online